Let 1 2 3 1 1 A = -2 -2 3 3 1 2 -2 -3 (a) Use the elimination method to evaluate det(A). (b) Use the value of det(A) to evaluate 3 3 -2 -2 3 3 1 1 1 2 -2 -3 -1 4 3 -1 -2 4.

Find the value of x. (a) (b) (c) (d) 3 4 (f) X = 3 5 = X = 580 = || w|N II (e) 5 X = o|م = X = = = X = 5 12 X 6 36 X = X 12 = X 20 X 27 X 24 X 48

Use the table to evaluate the given compositions. a. h(g(-3)) d. g(h(f(-1))) g. f(h(g(-2))) j. f(f(h(-1))) b. g(f(2)) e. f(f(f(1))) h. g(f(h(-1))) c.h(h(1)) f.h(h(h(-1))) i. g(g(g(-2))) X f(x) g(x) h(x) ♡~♡~ 2 -3 TI ~ T -2 - 1 1 -1 I 1 -1 -1 ON NO -2 FON 0 NONN 2 -2 0 -3

Q3. The table below shows the rate of charges for taxi fare. Booking Fee Monday to Friday - 7.00 a.m. to 9.30 a.m. 5.00 p.m. to 11.00 p.m. $4.00 $2.50 All other times (including Saturday, Sunday and all Public Holidays $2.50 Charges for 1st km or less $0.10 Charges for every 200 meters thereafter Mr Lee booked a taxi at 10.00 a.m. His taxi fare came up to $9. What was the maximum distance he could have travelled?