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Asked Dec 5, 2019
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Let f : R → Z, where f(x) = [2x – 1].
(a) Find f(A), where A = {x € R | 1< x < 4}.
(b) Find f-'(B), where B = {-9, –8}.
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Let f : R → Z, where f(x) = [2x – 1]. (a) Find f(A), where A = {x € R | 1< x < 4}. (b) Find f-'(B), where B = {-9, –8}.

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f(x)=[2x –1]. f:R→Z. (a) Find the values of f(A) as follows. Given that, A={reR|1<x<4}. If f(1)=1, f(4) =7. That is, [2x -1]e[1,7]. f(x)=[2x –1]=1 if1< f(x)<2 f(x) =[2x - 1]=2 if 2s f(x)<3 S(x) =[2x -1]=3 if 3 < f (x)<4 f(x) =[2x -1]=4 if 4< f(x)<5 f(x) =[2x – 1]=5 if 5< f(x)<6 f(x) =[2x -1]=6 if 6 < f(x)<7 f(x)=[2x -1]=7 if f(x)=7 %3D Thus, the values of f (x)= {1,2,3,4,5,6,7}.

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