Question
Asked Dec 15, 2019
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Let f(x)
1 + x2 '
(a) Find the absolute maximum and minimum values of f on the interval [0, 3].
+1
du
Idu o
X.
dp
du
du
(b) Find the exact value of the area between the curve y = f(x) and the x-axis for 0 <x < 3.
%3D
dx
du
0
U=1+X2
du 2b de
lu
6. (a) The graph of a twice-differentiable function a is shown below. Put these quantities in
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Let f(x) 1 + x2 ' (a) Find the absolute maximum and minimum values of f on the interval [0, 3]. +1 du Idu o X. dp du du (b) Find the exact value of the area between the curve y = f(x) and the x-axis for 0 <x < 3. %3D dx du 0 U=1+X2 du 2b de lu 6. (a) The graph of a twice-differentiable function a is shown below. Put these quantities in

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Expert Answer

Step 1

Given,

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f (x) =; 1+x?

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Step 2

Part (a):

Find the absolute maximum and minimum values of the function f(x) on the interval [0, 3].

On differentiating with respect to x, it gives

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(1+ x² )×1- x(0+2x) (1+ x*)* f '(x) = 1+x² - 2x? (1+ x*)* 1-x2 (1+x²)*

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Step 3

Now put f ‘ (...

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1-x? = 0 (1+x*) 1-x = 0 x =1 x = ±1

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Tagged in

Math

Calculus

Integration