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Let f(x)=2x^2-3x+7/4x^2+4x+6. Evaluate f'(x) at x=5.f'(5)=

Question

Let f(x)=2x^2-3x+7/4x^2+4x+6. Evaluate f'(x) at x=5.

f'(5)=

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Step 1

We have to differentiate f(x)and find value at x=5 , where f(x) is given by 

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Step 2

We will use power rule ,quotient rule to find...

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Math

Calculus

Derivative

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