Question
Let g be the function defined by g(x) = -x? + 6x. Find g(a + h), g(-a), g(vā), a + g(a), and -
g(a)
g(a + h) = -(a+ h)² + 6(a + h)
g(-a)
-а? — ба
-a² + 6va
1
a + g(a)
| 6a – a²
1
g(a)
ба — а?

Image Transcription

Let g be the function defined by g(x) = -x? + 6x. Find g(a + h), g(-a), g(vā), a + g(a), and - g(a) g(a + h) = -(a+ h)² + 6(a + h) g(-a) -а? — ба -a² + 6va 1 a + g(a) | 6a – a² 1 g(a) ба — а?

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Tagged in
MathCalculus

Functions