Question
Asked Oct 15, 2019

Find the equation of the tangent line.

Let g(s)
e (s2 +2)
a) Find the equation of the tangent line to g at (0, 2)
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Let g(s) e (s2 +2) a) Find the equation of the tangent line to g at (0, 2)

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Expert Answer

Step 1

We have to find the slope at (0,2)

For that we need g'(0)

Step 2

Calculate g'(x) using product rule.

g(s)=e*(s2+2)
g'(s)=(e')(s2+2)+e°(s2+2)
g'(s) e (s2+2)+e'(2s)
g'(s) e(s2+2s+2)
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g(s)=e*(s2+2) g'(s)=(e')(s2+2)+e°(s2+2) g'(s) e (s2+2)+e'(2s) g'(s) e(s2+2s+2)

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Step 3

Plug s=0 in g'(s) to find g'(...

g'(s) e(s2+2s+2)
g'(0)=e°(0+2(0)+2)
g'(0)=1(2)
g'(0)=2
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g'(s) e(s2+2s+2) g'(0)=e°(0+2(0)+2) g'(0)=1(2) g'(0)=2

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