Question
Asked Nov 9, 2019
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Let h(t) = tan t.

Find the maximum and minimum values of h on the interval I = [0, π/6]. Then use the Comparison Property to find upper and lower bounds for the area of the region between the graph of h and the x axis on the interval I.

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h(x) tanx h'(x) = sec2x Since the slope is positive as it is a squared function, the given function is an increasing function The maximum and minimum values occur at the end of the given intervals 1 Maximum value occurs at x 6 = tan 6 0.577 V3 Minimum value occurs at x = 0; h(0) = tan 0 = 0

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Calculus

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