Let R= Z/5Z, the integers mod 5. The ring of Gaussian integers mod 5 is defined by R[i] = {a+ bi : a, be Z/5Z and i=-1}. Show that R[i} is not an integral domain (and hence not a field) by showing that 3+i is a zero-divisor in R[i].

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter6: More On Rings
Section6.3: The Characteristic Of A Ring
Problem 4E
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Let R= Z/5Z, the integers mod 5. The ring of Gaussian integers mod 5 is defined
by R[i] = {a+ bi : a, be Z/5Z and i=-1}. Show that R[i} is not an integral
domain (and hence not a field) by showing that 3+i is a zero-divisor in R[i].
Transcribed Image Text:Let R= Z/5Z, the integers mod 5. The ring of Gaussian integers mod 5 is defined by R[i] = {a+ bi : a, be Z/5Z and i=-1}. Show that R[i} is not an integral domain (and hence not a field) by showing that 3+i is a zero-divisor in R[i].
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