Let's solve the logarithmic equation log(3) + log(x – 2) = log(x). = log(x). (a) First, we combine the logarithms on the LHS to get the equivalent equation (b) Next, we use the fact that log is one-to-one to get the equivalent equation = x. (c) Now we find x =

Let's solve the logarithmic equation log(3) + log(x – 2) = log(x). = log(x). (a) First, we combine the logarithms on the LHS to get the equivalent equation (b) Next, we use the fact that log is one-to-one to get the equivalent equation = x. (c) Now we find x =

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter4: Exponential And Logarithmic Functions

Section4.5: Exponential And Logarithmic Equations

Problem 2E: Let's solve the logarithmic equation log 3 + log(x — 2) = log x (a) First. we the logarithms on LHS...

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Question

Let's solve the logarithmic equation
log(3) + log(x – 2) = log(x).
= log(x).
(a) First, we combine the logarithms on the LHS to get the equivalent equation
(b) Next, we use the fact that log is one-to-one to get the equivalent equation
= x.
(c) Now we find x =

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