LuS)3-3.-4. Mass Transfer to Definite Shapes. Estimate the value of the mass-transfer coeffcient in a stream of air at 325.6 K flowing in a duct past the following shapes made ofsolid naphthalene. The velocity of the air is 1.524 m/s at 325.6 K and 202.6 kPa. TheDAB of naphthalene in air is 5.16 x 10% m2/s at 273 K and 101.3 kPa.(a) For air flowing parallel to a flat plate 0.152 m in length(b) For air flowing past a single sphere 12.7 mm in diameter-5АВ1.21 1,22

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Asked Oct 22, 2019
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LuS)
3-3.
-4. Mass Transfer to Definite Shapes. Estimate the value of the mass-transfer coeff
cient in a stream of air at 325.6 K flowing in a duct past the following shapes made of
solid naphthalene. The velocity of the air is 1.524 m/s at 325.6 K and 202.6 kPa. The
DAB of naphthalene in air is 5.16 x 10% m2/s at 273 K and 101.3 kPa.
(a) For air flowing parallel to a flat plate 0.152 m in length
(b) For air flowing past a single sphere 12.7 mm in diameter
-5
АВ
1.21 1,22
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LuS) 3-3. -4. Mass Transfer to Definite Shapes. Estimate the value of the mass-transfer coeff cient in a stream of air at 325.6 K flowing in a duct past the following shapes made of solid naphthalene. The velocity of the air is 1.524 m/s at 325.6 K and 202.6 kPa. The DAB of naphthalene in air is 5.16 x 10% m2/s at 273 K and 101.3 kPa. (a) For air flowing parallel to a flat plate 0.152 m in length (b) For air flowing past a single sphere 12.7 mm in diameter -5 АВ 1.21 1,22

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Step 1

First, find correct DAB at 325.6 K and 202.6 kPa using the relation as shown below:

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D.: с AB 3/2 (D&B (D) (1) Tr P. (D&B5.16x10 m2/s АВ T 273 K Т, %3 325.6 K P 101.3 kPa P 202.6 kPa Substitute these values in equation (1) and solve for (D1), as 3/2 273 5.16x 10 202.6 (DiB) 101.3 325.6 (DAB3.36x105 m2/s

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Step 2

Sherwood number (Sh), Schmidt number (Sc), and Reynolds number (Re) to be used further are defined as:

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hL (2) Sh DAB (3) Sc pDAB dvp Re (4) Here h convective heat transfer coefficient (m/s) L characteristic length (m D& mass diffusivity (m2/s) viscosity of the fluid (kg/m s) AB p=density (kg/m2) d length of the plate (m) v velocity of the fluid (m/s)

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Step 3

Part (a)

 

Use Colburn J-factor analogy is written as equation (5). For flow o...

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Sh JM (5) ReScV JM 0.663Re0.5 (6) Compare equation (5) and (6) such that; Sh 0.663Re 0.5 RESCV Sh 0.663Sc Re05 (7)

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