Question
Asked Nov 15, 2019
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A block of mass m = 5.7 kg is pulled up a θ = 22° incline as in the figure below with a force of magnitude F = 33 N. 

Find the acceleration of the block if the incline is frictionless. (Give the magnitude of the acceleration.)

Find the acceleration of the block if the coefficient of kinetic friction between the block and incline is 0.12. (Give the magnitude of the acceleration.)

m
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m

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Expert Answer

Step 1

(a)

Consider the surface is frictionless, and then the net force acting along the inclined plane is.

Substitute the values,

F' F-mgsin0
F' 33N-(5.7kg) (9.80 m/s )sin (22°)
=12.1N
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F' F-mgsin0 F' 33N-(5.7kg) (9.80 m/s )sin (22°) =12.1N

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Step 2

According to the Newton’s second law, find the acceleration of the block.

Substitute the values,

а:
т
12.1N
а:
5.7kg
2
= 2.12m/s
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а: т 12.1N а: 5.7kg 2 = 2.12m/s

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Step 3

(b)

Consider the surface is acting now the friction force, then the ne...

Ft F-mgsin 0-umg cos e
net
at335.7kg)(9.8m/s)sin(220)-(0.12)(5.7 kg) (9.8m/s) cos (220)
net
=33N -20.9N-6.22N
= 5.88N
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Ft F-mgsin 0-umg cos e net at335.7kg)(9.8m/s)sin(220)-(0.12)(5.7 kg) (9.8m/s) cos (220) net =33N -20.9N-6.22N = 5.88N

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Newtons Laws of Motion

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