Ma ASapling Learning A solution of a specific vitamin has Amax = 283 nm and a concentration of 7.16 x 107 M. The absorbance of th solution at 283 nm is A = 0.150. What is the molar absorptivity of the vitamin at 283 nm? (sample pathlength 1.00 cm) Number -1 L mol cm 5. Exit Next Check Answer Give Up & View Solution Previous Hint reb search
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- What percentage of the recommended daily dose of calcium (1,150 mg/day) does 1.0 L of your water provide? Show all calculations. Tap Water Trial 1 Tap Water Trial 2 Tap Water Trial 3 Initial Syringe Reading 1.0ml 1.0ml 1.0ml Final Syringe Reading 0.65ml 0.68ml 0.67ml Volume of EDTA Consumed 0.35ml 0.32ml 0.33ml Water Hardness ppm CaCO3 70.07 ppmCaCO3 64.064 ppmCaCO3 66.066 ppmCaCO3 Average ppm 66.73 ppmCaCO3Based on your value of Ksp1 what is the solubility of borax in the room temperature solution? Trial 1: 0.0141 T2: 0.015 AVG: 0.0139 Temp: 293.15K1) The ratio strength of a 10mL vial of neostigmine methylsulfate injection USP is 1:1500. Calculate the amount of neostigmine methylsulfate in milligrams contained in the 10mL vial. (Round to the whole number).
- 1. What is the MW of the analyte?2. What is the meq of the analyte?3. What is the weight (in grams) of the analyte?4. What will be the percentage purity of the sample if 43mL of the titrant was consumed?5. Did the sample conform to the USP requirement? Yes or No?A 60-year-old woman who weighs 75kg requires a loading dose of an antibiotic to treat an infection. A plasma concentration of 4.5 mg/L of the antibiotic needs to be achieved for optimal therapeutic effectiveness. The volume of distribution (Vd) of this antibiotic is 0.2 L/kg. The salt factor (S) is 0.6 and bioavailability fraction (F) is 1. The antibiotic is available as a 100 mg/mL infusion.Loading dose = Amount of drug in the bodyBioavailability (F) x Salt fraction (S)Amount of drug in the body = Target conc. (C) x Volume of distribution (Vd)How many millilitres of antibiotic infusion need to be administered?State your answer to 1 decimal place.unit- mlDensity of solution:Trial 1: 1.2 g/mLTrial 2: 1.2 g/mLTrial 3: 1.2 g/mL Average density = 1.2 g/mL What is the relative average deviaion, %?
- You are provided with a stock standard with a concentration of 100 mg/L, and a solution of unknown concentration. Prepare calibration standards using a 10 mL volumetric flask and a 1 mL piston pipette, and measure on the UV/Vis spectrophotometer (400 nm). Determine the concentration of the unknown after a 1:40 dilution, and provide the concentration of the initial solution. i need to learn how to do the calculations and draw a calibration curve to find concentration of unknown sample after i find the absorbances.An unknown food-dye is analyzed by the method used in this experiment. The absorbance of 5 standard solutions is plotted vs. their concentration (molarity) and a straight line is obtained with the formula: Abs = 4.850x + 0 An unknown food-dye soluton is diluted and it's absorbance is found to be 0.55. What is the molarity of the diluted unknown?An unknown food-dye is analyzed by the method used in this experiment. The absorbance of 5 standard solutions is plotted vs. their concentration (molarity) and a straight line is obtained with the formula: Abs = 3.350x +0.08 An unknown food-dye soluton is diluted and it's absorbance is found to be 0.50. What is the molarity of the diluted unknown, to two significant figures?
- Q3) A solution of Tryptophan has an absorbance at 280 nm of 0.25 in a 0.5 cm length cuvette. Given the absorbance coefficient of Tryptophan is 6.4 × 103 L Mol-1 cm-1. What is the concentration of solution?analyte concentration(C)(mg/ml) injection volume (ul) elution time (time) peak DAD signal(mAU) caffeine 1 1 4.67 302.85 aspartame 5 1 7.53 15.83 benzoic acid 1 1 8.14 89.98 saccharin 1 1 1.91 84.86 mixture(add everything above with 1:1:1:1 ratio) 1 4.47 69.58 How to get the concentration of the mixture in this case?Table 5. Drink mix concentrations and absorbances for constructing a standard curve [H3O+] (M) [OH−] (M) pOH pH 2.00 1.0*10^-2 1.0*10^-12 pH 5.00 1.0*10^-5 1.0*10^-9 pH 7.00 1.0*10^-7 1.0*10^-7 pH 9.00 1.0*10^-9 1.0*10^-5 pH 12.00 1.0*10^-12 1.0*10^-2