Magnesium (used in the manufacture of light alloys) reacts with iron(III) chloride to form magnesium chloride and iron. 3Mg(s) + 2FeCl₃(s) → 3MgCl₂(s) + 2Fe(s) A mixture of 41.0 g of magnesium ( mm= 24.31 g/mol) and 175 g of iron(III) chloride ( mm= 162.2 g/mol) is allowed to react. MMof MgCl2=105.216 g/mol. 1. What is the limiting reactant? 2. how many grams of excess reactants will remain? 3. How many grams of MgCl2 will be formed? 4. If 142 g of MgCl2 were formed, what is the percent yeild for the reaction? No decimals.

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Chapter3: Calculations With Chemical Formulas And Equaitons
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Magnesium (used in the manufacture of light alloys) reacts with iron(III) chloride to form magnesium chloride and iron.

3Mg(s) + 2FeCl₃(s) → 3MgCl₂(s) + 2Fe(s)

A mixture of 41.0 g of magnesium ( mm= 24.31 g/mol) and 175 g of iron(III) chloride ( mm= 162.2 g/mol) is allowed to react. MMof MgCl2=105.216 g/mol.

1. What is the limiting reactant?

2. how many grams of excess reactants will remain?

3. How many grams of MgCl2 will be formed?

4. If 142 g of MgClwere formed, what is the percent yeild for the reaction? No decimals.

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