MAGNETISM (PHYS 1303, 1304,1307 &1308)AssignmentGradebookORIONDownloadable eTextbookhtFULL SCREENPRINTER VERSIONBACKNEXTChapter 28, Problem 005 GOAn electron moves through a uniform magnetic field given by BBxi+(3.06 Bx)j. At a particular instant, the electrone(1.93i+4.30j) m/s and the magnetic force acting on it is (3.32 x 1019)k N. Find Byhas velocity V =NumberUnitsthe tolerance is +/-2%Click if you would like to Show Work for this question: Open Show WorkQuestion Attempts: 0 of 5 usedSUBMIT ANSWERSAVE FOR LATERpowered byMapleNetVersion 4.24.16.22000-2019 John Wiley & Sons, Inc, All Rights Reserved. A Division of John Wiley & Sons, Inc.PolicyJTIDER. iT you receive10WMacBook AirF11F10IIF8F9F7F6F5

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Asked Oct 21, 2019
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MAGNETISM (PHYS 1303, 1304,
1307 &1308)
Assignment
Gradebook
ORION
Downloadable eTextbook
ht
FULL SCREEN
PRINTER VERSION
BACK
NEXT
Chapter 28, Problem 005 GO
An electron moves through a uniform magnetic field given by B
Bxi+(3.06 Bx)j. At a particular instant, the electron
e
(1.93i+4.30j) m/s and the magnetic force acting on it is (3.32 x 1019)k N. Find By
has velocity V =
Number
Units
the tolerance is +/-2%
Click if you would like to Show Work for this question: Open Show Work
Question Attempts: 0 of 5 used
SUBMIT ANSWER
SAVE FOR LATER
powered by
MapleNet
Version 4.24.16.2
2000-2019 John Wiley & Sons, Inc, All Rights Reserved. A Division of John Wiley & Sons, Inc.
Policy
JTIDER. iT you receive
10
W
MacBook Air
F11
F10
II
F8
F9
F7
F6
F5
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MAGNETISM (PHYS 1303, 1304, 1307 &1308) Assignment Gradebook ORION Downloadable eTextbook ht FULL SCREEN PRINTER VERSION BACK NEXT Chapter 28, Problem 005 GO An electron moves through a uniform magnetic field given by B Bxi+(3.06 Bx)j. At a particular instant, the electron e (1.93i+4.30j) m/s and the magnetic force acting on it is (3.32 x 1019)k N. Find By has velocity V = Number Units the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work Question Attempts: 0 of 5 used SUBMIT ANSWER SAVE FOR LATER powered by MapleNet Version 4.24.16.2 2000-2019 John Wiley & Sons, Inc, All Rights Reserved. A Division of John Wiley & Sons, Inc. Policy JTIDER. iT you receive 10 W MacBook Air F11 F10 II F8 F9 F7 F6 F5

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Expert Answer

Step 1

Let v be the velocity of the electron, q be the charge of an electron, B be the magnetic field, and F be the force acting on the electron due to magnetic field acting on it.

Write the given values of question.

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B (Bi3.06Bj) T v(1.93i +4.30j) m/s F (3.32x 1019k N

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Step 2

Write the expression for force acting on a charged particle due to magnetic field in vector form.

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- (1.6 x1019 C) (1.93i+ 4.30j) m/s)x ((B,i+3.06B.j) T) N =(1.6 x1019 C)(5.9058B, k - 4.30B,k) N =2.56928 x10-19B k N

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Step 3

Compare the above force value with the force value given i...

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F 2.56928x10 B,k N- (3.32x 1019k) N 3.32x 10-19 В. 2.56928x 1019 X = 1.292 T

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