Chem 1121
me Section # 5. An aqueous solution is prepared by dissolving 0.415 g of KMnO4 in 250.0 mL of water. This solution is then diluted by taking a 25.0 mL aliquot (sample) and diluting it to 100.0 mL with water. A third solution is then prepared by taking 10.0 mL of the diluted solution and further diluting it to 50.0 mL with water. Show how to determine (and then calculate) the molarity of each solution (the 3 different solutions prepared). The molarity of the first solution (initial solution) is: The molarity of the second solution (1st dilution) is: The molarity of the third solution (2nd dilution) is:
Molarity is given by,
Molarity = mole/liter
The concentration of diluted solution is calculated by using volumetric formula, it is
VM=V,M2 where, V-initial volume M-initial molarity V,final volume M2-finalmolarity
Molarity of first solution is calculated as,
1mol KMnO 158.034 g KMnO4 0.250L 1L 0.415g KMnO 0.0105M
Molarity of second solutio...
0.025L x0.0105M=0.100 Lx M 0.025Lx0.010M M --0.0026M 0.100L
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