meSection #5. An aqueous solution is prepared by dissolving 0.415 g of KMnO4 in 250.0 mL of water. Thissolution is then diluted by taking a 25.0 mL aliquot (sample) and diluting it to 100.0 mL with water.A third solution is then prepared by taking 10.0 mL of the diluted solution and further diluting it to50.0 mL with water. Show how to determine (and then calculate) the molarity of each solution (the3 different solutions prepared).The molarity of the first solution (initial solution) is:The molarity of the second solution (1st dilution) is:The molarity of the third solution (2nd dilution) is:

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Asked Nov 28, 2019
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Chem 1121

me
Section #
5. An aqueous solution is prepared by dissolving 0.415 g of KMnO4 in 250.0 mL of water. This
solution is then diluted by taking a 25.0 mL aliquot (sample) and diluting it to 100.0 mL with water.
A third solution is then prepared by taking 10.0 mL of the diluted solution and further diluting it to
50.0 mL with water. Show how to determine (and then calculate) the molarity of each solution (the
3 different solutions prepared).
The molarity of the first solution (initial solution) is:
The molarity of the second solution (1st dilution) is:
The molarity of the third solution (2nd dilution) is:
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me Section # 5. An aqueous solution is prepared by dissolving 0.415 g of KMnO4 in 250.0 mL of water. This solution is then diluted by taking a 25.0 mL aliquot (sample) and diluting it to 100.0 mL with water. A third solution is then prepared by taking 10.0 mL of the diluted solution and further diluting it to 50.0 mL with water. Show how to determine (and then calculate) the molarity of each solution (the 3 different solutions prepared). The molarity of the first solution (initial solution) is: The molarity of the second solution (1st dilution) is: The molarity of the third solution (2nd dilution) is:

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Expert Answer

Step 1

Molarity is given by,

Molarity = mole/liter

The concentration of diluted solution is calculated by using volumetric formula, it is

VM=V,M2
where,
V-initial volume
M-initial molarity
V,final volume
M2-finalmolarity
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VM=V,M2 where, V-initial volume M-initial molarity V,final volume M2-finalmolarity

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Step 2

Molarity of first solution is calculated as,

1mol KMnO
158.034 g KMnO4 0.250L
1L
0.415g KMnO
0.0105M
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1mol KMnO 158.034 g KMnO4 0.250L 1L 0.415g KMnO 0.0105M

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Step 3

Molarity of second solutio...

0.025L x0.0105M=0.100 Lx M
0.025Lx0.010M
M
--0.0026M
0.100L
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0.025L x0.0105M=0.100 Lx M 0.025Lx0.010M M --0.0026M 0.100L

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