Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C, He Os, with methanol, CH3 OH. C;H6 O3 + CH3OH → C3 Hs O3 + H20 In an experiment, 1.40 g of salicylic acid is reacted with 13.1 g of methanol. The yield of methyl salicylate, Cg Hs O3, is 1.34 g. What is the percentage yield? Percentage yield = Submit Answer Try Another Version 6 item attempts remaining

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
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Chapter3: Chemical Reactions
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Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C7 He O3, with methanol, CH3 OH.
C;H; O3 + CH3 OH → C3 Hs O3 + H2O
In an experiment, 1.40 g of salicylic acid is reacted with 13.1 g of methanol. The yield of methyl salicylate, C; Hs O3 , is 1.34 g. What is the percentage yield?
Percentage yield =
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Transcribed Image Text:Methyl salicylate (oil of wintergreen) is prepared by heating salicylic acid, C7 He O3, with methanol, CH3 OH. C;H; O3 + CH3 OH → C3 Hs O3 + H2O In an experiment, 1.40 g of salicylic acid is reacted with 13.1 g of methanol. The yield of methyl salicylate, C; Hs O3 , is 1.34 g. What is the percentage yield? Percentage yield = Submit Answer Try Another Version 6 item attempts remaining
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