Q: How many mL of a 15% (w/v) solution must be to deliver 8.0 g of solute? administered
A:
Q: A 12.5 % by mass solution of ethanol (C2H5OH) in water has a density of 1.225 g/mL at 20°C. What is…
A:
Q: Reagent nitric acid is 70.04% HNO3 by mass and its molarity is 14.84 M. Calculate its molality.…
A: Molarity is defined as moles of solute present per L of solution. Its unit is mol/L. Molality is…
Q: A HNO3 solution has a sp.gr. of 1.42 and is 70.0 % (w/w) HNO3. Express its concentration in (a)…
A: Given: Specific gravity of HNO3 = 1.42 Percentage w/w of HNO3 = 70.0 %…
Q: A saline solution is 0.9%m/v at 25oC. The ρsolution = 1.045g/ml. Find: (a) freezing point of the…
A: Answer: 0.9% (m/v) saline solution suggests that in 100mL solution 0.9g NaCl is present.
Q: Molarity, M, is defined as Select one: a. moles of solute dissolved in 1 mol of solvent. b. moles of…
A: Here, we have to define the term Molarity. Molarity gives an idea about the concentration of the…
Q: Which solution has the highest molarity? 2.0 moles of NaCI dissolved in 3.0 liters of solution O 6.0…
A: Solution stoichiometry involves the calculation of concentration of solutions in the given…
Q: Calculate the grams of solute in each of the following solutions: (а) 1.0 L of 12 М H-SO4 g H2SO4 х…
A: Given information: Volume of H2SO4 = 1.0 L Molarity of H2SO4 = 12 M Volume of KMnO4 = 75.9 mL…
Q: What is the molarity, M, of a solution that contains 10.58 g of NaCl (58.44 g/mol) in 407.504 mL of…
A:
Q: 1. The freezing point of an aqueous solution that contains a non- electrolyte is –9.0°C.
A: Solution:- Given:- Freezing point of aqueous solution containing non-electrolyte = -9.0°C. As, we…
Q: moles of solute Molarity Molarity = liters of solution 1. Determine the molarity of these solutions:…
A: a) M= 4.672.04 = 2.w89 M b)M= 0.6291.5 =0.4193 M c) M= 4.783×1106×10 =…
Q: A 5 percent solution (by mass) of cane-sugar (M.W. 342) is isotonic with 0.877% solution of…
A:
Q: A 12.5 % by mass solution of ethanol (C2H5OH) in water has a density of 1.225 g/ml at 20°C. What is…
A:
Q: Q-6- ASElufion Contains 41o.3 grams of Hz So perliter of Solution at 20°c If the density is…
A: Molality: In 1000 mL or 1L of the solution, the number of moles of the solute present is called the…
Q: A 12.5 % by mass solution of ethanol (C2H5OH) in water has a density of 1.225 g/mL at 20°C. What is…
A: In this question, we will findout the Molarity of the Solution. How you will determine the Molarity…
Q: What is the mole fraction of solute in a solution that has 3.50g sucrose (MM=342) and 100.0g water…
A:
Q: A 1.00 % by mass solution of lactose (C12H22011, 342.30 g/mol) in water has a density of 1.0602 g/mL…
A: Given, density of Solution = 1.0602 g/mL Mass % lactose = 1.00 % Molar mass of lactose = 342.30…
Q: What is the percent by mass of NaCl in a 100 g of solution that contains 0.390 mol of NaCl. At. wt.…
A: Percent by mass of NaCl Is calculated by calculating mass of NaCl.
Q: 5. What masses of KOH and water are needed to make 1500g of 20% solution? MW- K:39, O:16, H:1
A: Weight of solution = 1500 gm Percentage = 20%
Q: At what temperature will a 1 m aqueous solution boil if the solute's K, is 4°C/m? ΔΤ Кът %3D…
A: The elevation in boiling point of solution is given by the formula ∆Tb = Kbm…
Q: Reagent nitric acid is 65.73% HNO3 by mass and its molarity is 15.84 M. Calculate its molality.…
A:
Q: 21/ The molarity and Normality for 250 * ?ml of 1.05% NaHCO3 0.05, 0.05 U.1, 0.05 0.05,0.1 O Qz/…
A: 1. Given volume of NaHCO3 solution is 250mL. Concentration of NaHCO3 solution is 1.05%(m/V). What is…
Q: A solution is prepared by dissolving 1g of LiF in 10g of H2O. In this solution LiF is the a. Solute…
A: A solute is the species which is present in less amount and solvent is the species which is present…
Q: If 90g of CaBr2 is dissolved in C2H3O2 to make 9L of the solution, what is its normality? MW- Ca:…
A:
Q: There are three solutions prepared by dissolving (a) Dissolve 0.655 mol of citric acid, C6H8O7 in 1…
A: The solution concentration can be expressed by its molarity, molality, formality and normality. The…
Q: A solution is prepared by dissolving 19.264 g of KHC2204.H2C2O4.2H2O in water diluted to 900 mL. If…
A: Mass of KHC2O4.H2C2O4.2H2O = 19.264 grams Molar mass of KHC2O4.H2C2O4.2H2O = 254.19 grams Gram…
Q: 4.) "Rubbing alcohol" is a mixture of isopropyl alcohol (C3H,OH) and water that is 70 percent…
A: Given mass percent of C3H7OH = 70℅ density of solution = 0.79 g/ml
Q: Please help me with my hw. Please answer letters C-E tysm❤️ ACTIVITY: Solve for the following.…
A: Given data, The mass of sucrose = 10 g The molar mass of sucrose = 343 g The mass of water = 50 g…
Q: A solution of 34.5 (unknown) in 45g of water freezes at -19.2°. What is the molar mass of the…
A:
Q: B. Calculate the molality of a water solution if the freezing point is: 6. -9.3°C 7. -27.9°C 8.…
A: Here we are required to find the molality of the of water solution form the given freezing…
Q: Calculate the number of mmoles of solute that are present in 3400 ml of an aqueous solution that…
A: The volume of the solution is = 3400 mL The concentration of AgNO3 in the solution is = 4000 ng/mL…
Q: Calculate the molarity (M) of 34% aqueous H3PO4 solution (d=1.2g/ml). (P:31, O:16 H:1 g/moles)
A: 100 g of solution contains 34 g H3PO4. Density of solution = 1.2 g/mL=1200g/L [ 1mL=10-3L] Now…
Q: Calculate the freezing point of the solution when 3.54 moles of non-electrolyte is dissolved in…
A: Given , moles of non electrolyte = 3.54 mol mass of water = 0.678 kg Kf (for water )=-1.86 °C kgmol
Q: A 250 mL of 1% m/v Na2CO3 (MW = 105.99 g/mol) was found to have a density of 1.05 g/mL at 25oC. Find…
A:
Q: A 20% wt/wt aqueous solution of NaCl (58.45) at 25 oC has a density of 1.145 g/mL. Express the…
A:
Q: Calculate the normality of a solution of acetic acid ( CH3COOH) which contains 90g of acetic acid in…
A: Given data: Weight of Acetic acid (CH3COOH) = 90 g Make up volume = 2 L Atomic weight of Carbon (C)…
Q: Bam makes a second solution, adding 6.64 g of Co(CH3COO)2 to 42.51 mL of H20. Calculate the…
A: Given: Mass of Co(CH3COO)2 = 6.64 g And volume of water = 42.51 mL. Mass of water = density X volume…
Q: following
A: “Since you have posted a question with multiple sub-parts, we will solve first three sub- parts for…
Q: 1 18. A solution that is 33.6 % by mass of phenol (C&HSOH) in water is prepared. What is the mole…
A: Answer 19 :- 1.35 m is 1.35 mole of solute in 1 kg of water. (1000 g H2O) / (18.01532 g H2O/mol) =…
Q: Solute: H2SO4 Composition of Solution: mole% H2SO4 = 40 % Density, g/mL: 20 degrees: 1.681 ; 80…
A: In the question, we have a solute given which is Sulphuric acid The molecular weight of sulphuric…
Q: bons in ppim (by mass). 13.58 An automobile antifreeze mixture is made by mixing equal volumes of…
A: Given that: Density of EG =1.114 g/mol Density of water =1.0 g/molDensity of…
Q: Calculate the molality of a solution prepared by dissolving 135 grams of copper(II) sulfate (FW…
A: Solution - Molality - Molality is a measure of the number of moles of solute in a solution…
Q: A solution contains 25.5 g of NaCl dissolved in sufficient water to give a total mass of 325.0 g.…
A: Finding Molality as per question need and providing the solution related to question in step-2
Q: Find the molality of a solution made by adding 8g of NaOCI to 5000g of water. (MW: Na-23 g/mol, O-16…
A:
Q: (1) How many grams of K2SO4 are contained in 50 mL of 0.200 M? (2) How many millimoles of K2SO4 are…
A: When one mole of any compound is dissolved in 1000 ml of solution is called the 1molar solution .
Q: A solution of 49.0% H2SO4 by mass has a density of 1.39 g/cm3 at 293 K. A 25.0-cm3 sample of this…
A: In 100 gm of solution, 49 gm is H2SO4 . Volume of solution = Mass / Density…
Q: Solute: HCl Composition of Solution: Wt% HCl = 25% Density, g/mL: 20 degrees: 1.149 ; 80 degrees:…
A: The question is based on the concept of solutions. we have to calculate molality, normality and PPM…
Q: A concentrated phosphoric acid solution is 85.5% H 3PO 4 by mass and has a density of 1.69 g/mL at…
A: Given that , Mass percent of H3PO4 = 85.5 % Density of H3PO4 solution = 1.69 g/mL Molarity of…
Step by step
Solved in 3 steps
- Calculate MW from Average EM. MW (g/mol) = n (eq/mole) x EM (g/eq) where n is the number of H+ ions titrated per moelcule of acid TRIAL # moles of OH- # moles of H+ # equivalents H+ Equivalent Mass (g/eq) 1 0.00264 0.00264 0.00264 113.26 2 0.003295 0.003295 0.003295 91.05 113.26 + 91.05 = 204.31/2 = 102.155 g/eq average EM Acid is Sulfamic Acid1.065g of MgO (Analyte) of 84.74% were treated w/ 50ml of 1.02N H2SO4 (Acidic Titrant), and 48.28 mL of NaOH (Base Titrant) 1.103N concentration MW of analyte: 40Meq of analyte: 0.02NaOH vol: 48.28 Compute for the meq weight consumed by the acidic titrant (g-meq)Calculate the solubility of silver chromate in water: Ag2CrO4 ----------- 2Ag + + CrO42- Express the response in ppm (parts per million) of Ag + (which is the same as µg Ag + / ml). Ks (Ag2CrO4), 1’2 10-12
- Sources of Error Determine the relationship between the observed/apparent value (EX) VERSUS that of the true value (ET) for the quantity being sought by writing either <, >, or = on the space provided. TOPIC: Measured mass of the precipitate 1. Overignition which causes the conversion of BaSO4 precipitate to BaO. EX _____ ET2. Precipitate was not washed thoroughly. Ex _____ ET TOPIC: Standardization of Titrant 3.Distilled water was not equilibrated to room temperature before the preparation of NaOH titrant. EX _______ ETIn the standardi zation of HCl using pure anhydrou s sodium carbonate as primarystandard for methy l orange as indica tor , 1.0 mL HCl was found to be equiva lent to 0.05gof sodium carbonate (MW =106). The no rmality of HCl isSources of Error Determine the relationship between the observed/apparent value (EX) VERSUS that of the true value (ET) for the quantity being sought by writing either <, >, or = on the space provided TOPIC: Measured mass of the precipitate 1. Filter paper was dried prior to filtration. EX _____ ET TOPIC: Standardization of Titrant 2. Distilled water was not equilibrated to room temperature before the preparation of NaOH titrant. EX ______ ET TOPIC: Determination of Molar Concentration of each component (Double Indicator Titration) 3. No blank correction EX ______ ET
- (a) I f t he molar solubilit y o f CaF2 at 35 °C i s1.24 x 10-3 mol/L, what is Ksp at this temperature? (b) It isfound that 1.1 x 10-2 g SrF2 dissolves per 100 mL of aqueoussolution at 25 °C. Calculate the solubility product forSrF2. (c) The Ksp of Ba(IO3)2 at 25 °C is 6.0 x 10-10. What isthe molar solubility of Ba(IO3)2?A 0.64 g sample containing KCl ( mw = 74.6 ) is dissolved in 50mL of water and titrated to the Ag2CrO4 end point, requiring 26.2 mL of 0.15 M AgNO3 .The %w/w KCl in the sample is ?(a) For the precipitation reaction: A+ + B– AB(s)Calculate the value of the equilibrium constant for 99.99% conversion to AB atthe equivalence point, assuming that the analyte content is 5.00 mmole and thetotal volume at the equivalence point is 100.00 mL.(b) What factors affect end-point sharpness in a precipitation titration? Explain.(c) Explain briefly why silver nitrate is an important reagent used in precipitationtitrations.(d) Mohr Method, Volhard Method and Fajans Method are commonly used for thevolumetric analysis of chlorides. Distinguish the three methods in terms of thetitrants and indicators used, and how the titrations are carried out.
- Knowing that Ksp of PbI2 = 10-⁷ find out if precipitate will form when mixing 100ml of 0.01 N Pb solution (NO3) 2 and 200ml of 0.01 M NaI solution1. 1093-g sample of impure Na2CO3 was analyzed by residual precipitimetry. After adding 50.00 mL of 0.06911 M AgNO3, the sample was back-titrated with 0.05781 M KSCN, requiring 27.36 mL to reach the endpoint. The percentage Na2CO3 (MW = 106.0 g/mole) in the tested sample is ________ % ? Note: Express final answer using least number of significant figures. 2. The alkalinity of natural waters is usually controlled by OH- (MW = 17.01 g/mole), CO3-2 (MW = 60.01 g/mole), and HCO3- (MW = 61.01 g/mole), which may be present singularly or in combination. Titrating a 10.0-mL sample to a phenolphthalein endpoint requires 38.12 mL of a 0.5812 M solution of HCl, and an additional 18.67 mL of the same titrant to reach the methyl orange endpoint. The composition of the sample is _________% CO3-2 and ___________ % OH- Note: Express final answers using least number of significant figures.A sample is analyzed for chloride by the Volhard method. From the following data, calculate the percentage of chloride present:Weight of sample = 6.0000 g dissolved and diluted to 200 mLAliquot used = 25.00 mL AgNO3 added = 40.00ml of 0.1234MKSCN for back titration = 13.20ml of 0.0930M