Molecular nitrogen (N2) reacts with water vapor to form nitrogen monoxide (NO) and molecular hydrogen (H2). At some temperature a reaction system containing all four gases has been allowed come to equilibrium and the partial pressures of the gases are: PN2 = 0.12 atm, PH20 = 0.082, PNO = 0.55 atm, and PH2 = 0.76 atm. %3D Another system contains the same reactants and products at the following pressures: PN2 = 0.15 atm, PH20 = 0.12, PNO = 0.87 atm, and PH2 = 0.76 atm. Is this second system at equilibrium? If not, how will the reaction shift to reach equilibrium? N2(g) + 2 H20(g)= 2 NO(g) + 2 H2(g)

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Chapter12: Gaseous Chemical Equilibrium
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2. Molecular nitrogen (N2) reacts with water vapor to form nitrogen monoxide (NO) and molecular hydrogen
(H2). At some temperature a reaction system containing all four gases has been allowed come to equilibrium
and the partial pressures of the gases are: PN2 = 0.12 atm, PH20 = 0.082, PNo = 0.55 atm, and PH2 = 0.76 atm.
Another system contains the same reactants and products at the following pressures: Pn2 = 0.15 atm, PH20 =
0.12, PNo = 0.87 atm, and P2 = 0.76 atm. Is this second system at equilibrium? If not, how will the reaction
shift to reach equilibrium?
N2(g) + 2 H20(g) = 2 NO(g) + 2 H2(g)
Transcribed Image Text:2. Molecular nitrogen (N2) reacts with water vapor to form nitrogen monoxide (NO) and molecular hydrogen (H2). At some temperature a reaction system containing all four gases has been allowed come to equilibrium and the partial pressures of the gases are: PN2 = 0.12 atm, PH20 = 0.082, PNo = 0.55 atm, and PH2 = 0.76 atm. Another system contains the same reactants and products at the following pressures: Pn2 = 0.15 atm, PH20 = 0.12, PNo = 0.87 atm, and P2 = 0.76 atm. Is this second system at equilibrium? If not, how will the reaction shift to reach equilibrium? N2(g) + 2 H20(g) = 2 NO(g) + 2 H2(g)
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