MP 5The fastest server in women's tennis is Sabine Lisicki, who recordeda serve of 131 mi/h (211 km/h) in 2014. Suppose that theacceleration of the ball was constant during the contact with theracketPart AIf her racket pushed on the ball for a distance of 0.14 m, what was the acceleration of the ball during her serve?Express your answer with the appropriate units.?LEValueUnitsSubmitRequest AnswerPart BWhat was the time interval for the racket-ball contact?Express your answer with the appropriate units.UnitsValueSubmitRequest AnswerWiBbType here to search

Question
Asked Sep 16, 2019
MP 5
The fastest server in women's tennis is Sabine Lisicki, who recorded
a serve of 131 mi/h (211 km/h) in 2014. Suppose that the
acceleration of the ball was constant during the contact with the
racket
Part A
If her racket pushed on the ball for a distance of 0.14 m, what was the acceleration of the ball during her serve?
Express your answer with the appropriate units.
?
LE
Value
Units
Submit
Request Answer
Part B
What was the time interval for the racket-ball contact?
Express your answer with the appropriate units.
Units
Value
Submit
Request Answer
Wi
Bb
Type here to search
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MP 5 The fastest server in women's tennis is Sabine Lisicki, who recorded a serve of 131 mi/h (211 km/h) in 2014. Suppose that the acceleration of the ball was constant during the contact with the racket Part A If her racket pushed on the ball for a distance of 0.14 m, what was the acceleration of the ball during her serve? Express your answer with the appropriate units. ? LE Value Units Submit Request Answer Part B What was the time interval for the racket-ball contact? Express your answer with the appropriate units. Units Value Submit Request Answer Wi Bb Type here to search

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check_circleExpert Solution
Step 1

(a) Using equation of motion, the acceleration is,

a =
2y
(211km/h)-(0km/h)
2(0.14m
(58.61m/s
2(0.14m)
=12268.33 m/s?
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Image Transcriptionclose

a = 2y (211km/h)-(0km/h) 2(0.14m (58.61m/s 2(0.14m) =12268.33 m/s?

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Step 2

(b) Using equation...

y=ut
0.14m (Om/s)t+(12268.33m/s)
2(0.14m
V12268.33m/s
=4.78x10s
= 4.78ms
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Image Transcriptionclose

y=ut 0.14m (Om/s)t+(12268.33m/s) 2(0.14m V12268.33m/s =4.78x10s = 4.78ms

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