Question
Asked Dec 4, 2019
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The figure(Figure 1) is the velocity-versus-time graph for a 1.3 kg object moving along the x-axis. Determine the work done on the object during each of the four intervals AB, BC, CD, and DE.

(m/s)
2
0
C D E
A
в с
-2
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(m/s) 2 0 C D E A в с -2

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Expert Answer

Step 1

Work done in each interval is equal to the change in kinetic energy in that interval

Consider the interval AB.

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W.= 0.5m(v- v) 0.5(1.3kg)(-2m/s)-(2m/s)) 0J

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Step 2

Consider the interval BC.

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Wsc = 0.5m(v – v}) = 0.5(1.3 kg)(-2m/s) -(-2m/s)*) = 0J

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Step 3

Consider the int...

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WED -0.5m(v-) 0.5(1.3kg)(0m/s)-(-2m/s)) --2.6J

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Science

Physics

Work,Power and Energy

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