n a sample of 150 Planter’s Mixed Nuts, 15 were found to be almonds.
(a) Construct a 95 percent confidence interval for the true proportion of almonds. (Use a z-value taken to three decimal places in your calculations. Round your answers to 3 decimal places.)
The 95% confidence interval is from _________ to ________ .
(b) May normality be assumed?
(c) What sample size would be needed for 95 percent confidence and an error of ±0.03?
Sample size _________
According to the provided details, the sample of 150 Planter’s Mixed Nuts has been taken out of which 15 are almonds.
Therefore,
Sample size (n) = 150
Sample proportion (p̂) = 0.1.
The formula to calculate the 95% confidence interval for population proportion is:
(a)
The critical value for 95% confidence level can be found using the z-table. That is,
Substitute the values in the confi...
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