NAME: DATE: QUESTION 5 (5 pt): What is the output? #include void swap (int a, int b) { int tmp = b; b a; = tmp; return; S.8. a } void swap2 (int &a, int &b) { int tmp b; b3D а; tmp; return; a } int main() { int x{100}, y{25}; Swap(x,y)i std::cout<< "x -" < x << ", y=" << y << std:: endl; x-100, y-25 ; swap2 (x,y); std::cout<< "x -" << x << ", y=" << y << std::endl; } end? I1 1 QUESTION 6 (5 pt): What is the output? #include void mystery ( int x[ ] , int n) { int temp; for (int i = 0; i < n / 2 - 1; i++) { temp *[i] *[n - i - 1] = temp; } } int main( f *[i]; X[n - i - 1] ; 11 00 Tay

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Question 5, output in C++

NAME:
DATE:
QUESTION 5 (5 pt): What is the output?
#include <iostream>
void swap (int a, int b) {
int tmp = b;
b
a;
= tmp;
return;
S.8.
a
}
void swap2 (int &a, int &b) {
int tmp
b;
b3D а;
tmp;
return;
a
}
int main() {
int x{100}, y{25};
Swap(x,y)i
std::cout<< "x -" < x << ", y=" << y << std:: endl;
x-100, y-25 ;
swap2 (x,y);
std::cout<< "x -" << x << ", y=" << y << std::endl;
}
end?
I1
1
QUESTION 6 (5 pt): What is the output?
#include <iostream>
void mystery ( int x[ ] , int n) {
int temp;
for (int i = 0; i < n / 2 - 1; i++) {
temp
*[i]
*[n - i - 1] = temp;
}
}
int main( f
*[i];
X[n - i - 1] ;
11
00 Tay
Transcribed Image Text:NAME: DATE: QUESTION 5 (5 pt): What is the output? #include <iostream> void swap (int a, int b) { int tmp = b; b a; = tmp; return; S.8. a } void swap2 (int &a, int &b) { int tmp b; b3D а; tmp; return; a } int main() { int x{100}, y{25}; Swap(x,y)i std::cout<< "x -" < x << ", y=" << y << std:: endl; x-100, y-25 ; swap2 (x,y); std::cout<< "x -" << x << ", y=" << y << std::endl; } end? I1 1 QUESTION 6 (5 pt): What is the output? #include <iostream> void mystery ( int x[ ] , int n) { int temp; for (int i = 0; i < n / 2 - 1; i++) { temp *[i] *[n - i - 1] = temp; } } int main( f *[i]; X[n - i - 1] ; 11 00 Tay
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