nousdeCENGAGE MINDTAPQ Search this courseapter 13 AssignmentCheck My Work2.3.eBook4.The calculations for a factorial experiment involving four levels of factor A, three levels of factor B, and three replications resulted in the followingA-Zdata: SST = 276, SSA = 23, SSB = 25, SSAB = 170.5.Set up the ANOVA table and test for significance using a= .05. Show entries to 2 decimals, if necessary. If the answer is zero enter "0".1.Source of Variation Sum of Squares Degrees of FreedomMean Squarep-value8.Factor AFactor BInteractionNEErrorActivate WindowsTotalGo to Settings to activateThe p-value for Factor A is less than .0158 P1/9/2020LL6.7,

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Asked Jan 20, 2020
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The caluations for a factorial experiment involving four levels of factor A, three levels of factor B, and three replications resulting in the following data: SST = 276, SSA=23, SSB = 25, SSAB =170.

Set up the ANOVA table and test for significance using a=0.5. Show entries to 2 decimals, if necessary.  If the answer is zeeo enter 0.

Factor A?

Factor B?

Interaction?

Error?

Total?

Thank you

 

nousde
CENGAGE MINDTAP
Q Search this course
apter 13 Assignment
Check My Work
2.
3.
eBook
4.
The calculations for a factorial experiment involving four levels of factor A, three levels of factor B, and three replications resulted in the following
A-Z
data: SST = 276, SSA = 23, SSB = 25, SSAB = 170.
5.
Set up the ANOVA table and test for significance using a= .05. Show entries to 2 decimals, if necessary. If the answer is zero enter "0".
1.
Source of Variation Sum of Squares Degrees of Freedom
Mean Square
p-value
8.
Factor A
Factor B
Interaction
NE
Error
Activate Windows
Total
Go to Settings to activate
The p-value for Factor A is less than .01
58 P
1/9/2020
LL
6.
7,
help_outline

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nousde CENGAGE MINDTAP Q Search this course apter 13 Assignment Check My Work 2. 3. eBook 4. The calculations for a factorial experiment involving four levels of factor A, three levels of factor B, and three replications resulted in the following A-Z data: SST = 276, SSA = 23, SSB = 25, SSAB = 170. 5. Set up the ANOVA table and test for significance using a= .05. Show entries to 2 decimals, if necessary. If the answer is zero enter "0". 1. Source of Variation Sum of Squares Degrees of Freedom Mean Square p-value 8. Factor A Factor B Interaction NE Error Activate Windows Total Go to Settings to activate The p-value for Factor A is less than .01 58 P 1/9/2020 LL 6. 7,

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Step 1

According to the provided information,

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Step 2

ANOVA Table can be calculated as:

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Step 3

Here,

...
Statistics homework question answer, step 3, image 1
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