# O KINETICS AND EQUILIBRIUMUsing the van't Hoff equation to predict K at a different tempera...At -15.3 °C the pressure equilibrium constant K 6.8 for a certain reaction.рHere are some facts about the reaction:The constant pressure molar heat capacity C- 2.74 J-mol KIf the reaction is run at constant pressure, the volume increases by 9.2%%.The initial rate of the reaction is 15. mol LYes.x10Using these facts, can you calculate K,at 0.82 °CNo.you said yes, then enter your answer at right. Round it to2 significant digits.IfYes, and K will bebiggercan you at least decide whether K atрIf you said no,Yes, and K, will besmaller0.82 °C will be bigger or smaller than K,15.3 °C?atNo.II

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Using the fax in the picture can you calculate KP at 0.82 Celsius Using the fax in the picture can you calculate KP at 0.82 Celsius if yes write it down if you said no can you at least decide where the KP at 0.82 Celsius will be bigger or smaller than KP and -15.3. help_outlineImage TranscriptioncloseO KINETICS AND EQUILIBRIUM Using the van't Hoff equation to predict K at a different tempera... At -15.3 °C the pressure equilibrium constant K 6.8 for a certain reaction. р Here are some facts about the reaction: The constant pressure molar heat capacity C- 2.74 J-mol K If the reaction is run at constant pressure, the volume increases by 9.2%%. The initial rate of the reaction is 15. mol L Yes. x10 Using these facts, can you calculate K, at 0.82 °C No. you said yes, then enter your answer at right. Round it to 2 significant digits. If Yes, and K will be bigger can you at least decide whether K at р If you said no, Yes, and K, will be smaller 0.82 °C will be bigger or smaller than K, 15.3 °C? at No. II fullscreen
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Step 1

Given that,

T1= 0.82 C

T2= -15.3 C

Kp= 0.82

ΔH= 2.74 J/mol.K

Step 2

Now using Vont Hoff equation you calculate Kp at -15.3C. help_outlineImage Transcriptionclose( Kp ) , -ΔΗ11 In (Кр), R T, т, Where, (KpPressure equiliberium constant at T (Kp) Pressure equiliberium constant atT T 273.82K Т, -2257.7K (Кр), 37 (Кр), —0.82 AH 2.74 Jmol1'K-1 fullscreen
Step 3

Putting these values in equation you... help_outlineImage Transcriptionclose2.74Jmol K 8.314Jmol K1 273.82K 257.7K 0.82 In К, 1 1 0.82 257.7-273.82 -0.3296 In К, 273.82x257.7 0.82 In -0.0000753 K1 0.82 =-7.53x10 In К, (Кр), —0.82 fullscreen

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