o. The height (feet) of an object moving vertically is given by s = -16t288t+216, where t is in seconds. Find the object's velocity at t 4, its maximum height and when it occurs, and its velocity when s0.The velocity of the object at t4 seconds is(Simplify your answer. Type an integer or a decimal.)ft/secondThe maximum height occurs at t=seconds.(Simplify your answer. Type an integer or a decimal.)The maximum height isfeet(Simplify your answer. Type an integer or a decimal.)feet/secondThe velocity when s 0 is(Round to the nearest hundredth.)

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Asked Nov 3, 2019
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o. The height (feet) of an object moving vertically is given by s = -
16t288t+216, where t is in seconds. Find the object's velocity at t 4, its maximum height and when it occurs, and its velocity when s
0.
The velocity of the object at t4 seconds is
(Simplify your answer. Type an integer or a decimal.)
ft/second
The maximum height occurs at t=
seconds.
(Simplify your answer. Type an integer or a decimal.)
The maximum height is
feet
(Simplify your answer. Type an integer or a decimal.)
feet/second
The velocity when s 0 is
(Round to the nearest hundredth.)
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o. The height (feet) of an object moving vertically is given by s = - 16t288t+216, where t is in seconds. Find the object's velocity at t 4, its maximum height and when it occurs, and its velocity when s 0. The velocity of the object at t4 seconds is (Simplify your answer. Type an integer or a decimal.) ft/second The maximum height occurs at t= seconds. (Simplify your answer. Type an integer or a decimal.) The maximum height is feet (Simplify your answer. Type an integer or a decimal.) feet/second The velocity when s 0 is (Round to the nearest hundredth.)

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Expert Answer

Step 1

Given:

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The height of an object moving vertically is given by s-162881 +216

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Step 2

Find the velocity when t = 4.

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ds The velocity can be calculated as v = dt d(-16+288+216 dt v-32t288 When t 4 v -32(4)288 160 ft/sec

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Step 3

At maximum height vel...

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-32t 288 0 >t=9 sec

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