Math

StatisticsQ&A LibraryOn average, indoor cats live to 14 years old with a standard deviation of 2.7 years. Suppose that the distribution is normal. Let X = the age at death of a randomly selected indoor cat. Round answers to 4 decimal places where possible. c. The middle 30% of indoor cats' age of death lies between what two numbers? Low: years High: yearsQuestion

Asked Mar 22, 2020

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On average, indoor cats live to 14 years old with a standard deviation of 2.7 years. Suppose that the distribution is normal. Let X = the age at death of a randomly selected indoor cat. Round answers to 4 decimal places where possible.

c. The middle 30% of indoor cats' age of death lies between what two numbers?

Low: years

High: years

Step 1

**Here, X follows the normal distribution with mean 14 years old and a standard deviation of 2.7 years. Let X be the age at death of a randomly selected indoor cat.**

**Compute the middle 30% of indoor cats’ age of death lies between the two numbers:**

First finding the z-score for the 35 percentiles.

Therefore,

Using the standard normal table, choose the corresponding row and column value nearer to the probability of 0.35. the z-score corresponding value nearer to 0.35 is -0.39.

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