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Social ScienceOn average, indoor cats live to 14 years old with a standard deviation of 2.7 years. Suppose that the distribution is normal. Let X = the age at death of a randomly selected indoor cat. Round answers to 4 decimal places where possible. c. The middle 30% of indoor cats' age of death lies between what two numbers? Low: years High: years
On average, indoor cats live to 14 years old with a standard deviation of 2.7 years. Suppose that the distribution is normal. Let X = the age at death of a randomly selected indoor cat. Round answers to 4 decimal places where possible.
c. The middle 30% of indoor cats' age of death lies between what two numbers?
Low: years
High: years
Expert Answer
Here, X follows the normal distribution with mean 14 years old and a standard deviation of 2.7 years. Let X be the age at death of a randomly selected indoor cat.
Compute the middle 30% of indoor cats’ age of death lies between the two numbers:
First finding the z-score for the 35 percentiles.
Therefore,
Using the standard normal table, choose the corresponding row and column value nearer to the probability of 0.35. the z-score corresponding value nearer to 0.35 is -0.39.
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