on the parabola when the line intersects, but does not cross, and graph the 51. x + 4x - 6y = 53. y2 + x + y = 0 16. Focus: G, 0) 18. Focus: (0, - 1) uation with O, and (d).] 15. Focus: (0,) 17. Focus: (-2, 0) 19. Directrix: y = 2 OO Finding a Parab equation at the gi 20. Directrix: y = -4 22. Directrix: x = 3 21. Directrix: x = - 1 %3D 23. Vertical axis; passes through the point (4, 6) 24. Vertical axis; passes through the point (-3, - 3) 25. Horizontal axis; passes through the point (-2, 5) 26. Horizontal axis; passes through the point (3, - 2) 55. x2 = 8y х 8. 4 DXO Finding the Standard Equation of a Parabola In Exercises 27-36, find the standard form of the equation of the parabola 4 -4 -4 with the given characteristics. 57. x = 2y, (4, 8 %3D 27. 28. Vertex 59. y = -2r², (- (2, 6) 61. Flashlight focus of the pa Focus (-3, 0) •Focus (2, 4) vertex of ther 4 8 12 Vertex a cross section (-4, 0) -8 on the positiv ation of a 6, find the the parabola nd vertex at -1 +1 2 3 4 5 6 29. Vertex: (6, 3); focus: (4, 3) 30. Vertex: (1, - 8); focus: (3, –8) 31. Vertex: (0, 2); directrix: y = 4 32. Vertex: (1, 2); directrix: y = -1 33. Focus: (2, 2); directrix: x = -2 34. Focus: (0, 0); directrix: y = 8 35. Vertex: (3, - 3); vertical axis; passes through the point (0, 0) 36. Vertex: (-1, 6); horizontal axis; passes through the point (-9, 2) Figure for 4. 62. Satellite dish is at th equation fo 76 4321

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter10: Analytic Geometry
Section10.1: The Rectangular Coordinate System
Problem 44E: By definition, a hyperbola is the locus of points whose positive difference of distances from two...
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How do you answer 33?

(This is not graded but, rather, an exercise to achieve acquisition).

on the parabola when the line intersects, but does not cross,
and
graph the
51. x + 4x - 6y =
53. y2 + x + y = 0
16. Focus: G, 0)
18. Focus: (0, - 1)
uation with
O, and (d).]
15. Focus: (0,)
17. Focus: (-2, 0)
19. Directrix: y = 2
OO Finding
a Parab
equation
at the gi
20. Directrix: y = -4
22. Directrix: x = 3
21. Directrix: x = - 1
%3D
23. Vertical axis; passes through the point (4, 6)
24. Vertical axis; passes through the point (-3, - 3)
25. Horizontal axis; passes through the point (-2, 5)
26. Horizontal axis; passes through the point (3, - 2)
55.
x2 = 8y
х
8.
4
DXO Finding the Standard Equation of a
Parabola In Exercises 27-36, find the
standard form of the equation of the parabola
4
-4
-4
with the given characteristics.
57. x = 2y, (4, 8
%3D
27.
28.
Vertex
59. y = -2r², (-
(2, 6)
61. Flashlight
focus of the pa
Focus
(-3, 0)
•Focus
(2, 4)
vertex of ther
4 8 12
Vertex
a cross section
(-4, 0)
-8
on the positiv
ation of a
6, find the
the parabola
nd vertex at
-1 +1 2 3 4 5 6
29. Vertex: (6, 3); focus: (4, 3)
30. Vertex: (1, - 8); focus: (3, –8)
31. Vertex: (0, 2); directrix: y = 4
32. Vertex: (1, 2); directrix: y = -1
33. Focus: (2, 2); directrix: x = -2
34. Focus: (0, 0); directrix: y = 8
35. Vertex: (3, - 3); vertical axis; passes through the point
(0, 0)
36. Vertex: (-1, 6); horizontal axis; passes through the
point (-9, 2)
Figure for
4.
62. Satellite
dish is at th
equation fo
76
4321
Transcribed Image Text:on the parabola when the line intersects, but does not cross, and graph the 51. x + 4x - 6y = 53. y2 + x + y = 0 16. Focus: G, 0) 18. Focus: (0, - 1) uation with O, and (d).] 15. Focus: (0,) 17. Focus: (-2, 0) 19. Directrix: y = 2 OO Finding a Parab equation at the gi 20. Directrix: y = -4 22. Directrix: x = 3 21. Directrix: x = - 1 %3D 23. Vertical axis; passes through the point (4, 6) 24. Vertical axis; passes through the point (-3, - 3) 25. Horizontal axis; passes through the point (-2, 5) 26. Horizontal axis; passes through the point (3, - 2) 55. x2 = 8y х 8. 4 DXO Finding the Standard Equation of a Parabola In Exercises 27-36, find the standard form of the equation of the parabola 4 -4 -4 with the given characteristics. 57. x = 2y, (4, 8 %3D 27. 28. Vertex 59. y = -2r², (- (2, 6) 61. Flashlight focus of the pa Focus (-3, 0) •Focus (2, 4) vertex of ther 4 8 12 Vertex a cross section (-4, 0) -8 on the positiv ation of a 6, find the the parabola nd vertex at -1 +1 2 3 4 5 6 29. Vertex: (6, 3); focus: (4, 3) 30. Vertex: (1, - 8); focus: (3, –8) 31. Vertex: (0, 2); directrix: y = 4 32. Vertex: (1, 2); directrix: y = -1 33. Focus: (2, 2); directrix: x = -2 34. Focus: (0, 0); directrix: y = 8 35. Vertex: (3, - 3); vertical axis; passes through the point (0, 0) 36. Vertex: (-1, 6); horizontal axis; passes through the point (-9, 2) Figure for 4. 62. Satellite dish is at th equation fo 76 4321
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