One of my homework problems asks this: A non-conducting sphere of radius R = 9.0 cm carries a charge Q = 5.0 mC distributed uniformly throughout its volume. At what distance, measured from the center of the sphere, does the electric field reach a value equal to half its maximum value? The correct answer is marked as 4.5 cm and 12.7 cm. I worked out: Emax = kQ/R2 for half the max electric field, i'll use R2 for radius we need to find Ehalf = kQ/2R2 = kQ/R22 giving me: R2 = square root of 2R2 = R*square root of 2 = 9*square root of 2 = 12.7 cm I am unable to figure out how 4.5 cm is also the answer.
One of my homework problems asks this: A non-conducting sphere of radius R = 9.0 cm carries a charge Q = 5.0 mC distributed uniformly throughout its volume. At what distance, measured from the center of the sphere, does the electric field reach a value equal to half its maximum value? The correct answer is marked as 4.5 cm and 12.7 cm. I worked out: Emax = kQ/R2 for half the max electric field, i'll use R2 for radius we need to find Ehalf = kQ/2R2 = kQ/R22 giving me: R2 = square root of 2R2 = R*square root of 2 = 9*square root of 2 = 12.7 cm I am unable to figure out how 4.5 cm is also the answer.
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter24: Gauss’s Law
Section: Chapter Questions
Problem 24.55AP: A solid insulating sphere of radius a = 5.00 cm carries a net positive charge of Q = 3.00 C...
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One of my homework problems asks this:
A non-
The correct answer is marked as 4.5 cm and 12.7 cm.
I worked out:
- Emax = kQ/R2
- for half the max electric field, i'll use R2 for radius we need to find
Ehalf = kQ/2R2 = kQ/R22
- giving me:
R2 = square root of 2R2 = R*square root of 2
= 9*square root of 2 = 12.7 cm
I am unable to figure out how 4.5 cm is also the answer.
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