# onLocator%3Dassignment-take[Review Topics][References]Use the References to access important values if needed for this question.The equilibrium constant, K, for the following reaction is 1.20×10-2 at 500 K.PCI5(g) PC3(g) + C2(g)An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.206 M PCls, 4.97×10-2 M PCI3 and 4.97x10 2 M Ch. What will be the concentrationsof the three gases once equilibrium has been reestablished, if 3.54x10 2 mol of PCI3(g) is added to the flask?[PCI5] =%3D[PC13]M[Ch]Submit AnswerRetry Entire Group7 more group attempts remainingPreviousNextSave and ExitMN

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Step 1

The reaction and the given data along with the calculation of equilibrium constant is given below:

Step 2

Given that 3.54×10-2 mol of PCl3 is added to the flask. We will insert the new initial concentrations in the ICE table and will solve for the equilibrium concentrations

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