On-Time Arrivals According to the Bureau of Transportation, American Airlines had an on-time arrival rate of 80.3% for a given year. Assume that this statistic is based on a sample of 1000 randomly selected American Airlines flights. Find the 99% confidence interval estimate of the percentage of all American Airlines flights that arrive on time.

Question
Asked Jan 13, 2020
1 views

On-Time Arrivals According to the Bureau of Transportation, American Airlines had an on-time arrival rate of 80.3% for a given year. Assume that this statistic is based on a sample of 1000 randomly selected American Airlines flights. Find the 99% confidence interval estimate of the percentage of all American Airlines flights that arrive on time.

check_circle

Expert Answer

Step 1

The formula for 100(1-α)% confidence interval for population proportion is,

Statistics homework question answer, step 1, image 1
fullscreen
Step 2

 

Here,

p: the sample proportion

ME: Margin of Error

n:sample size.

zα/2: critical value.

(1-α): Confidence level

Step 3

From the given information, the percentage of on-time arrival rate by American Airlines is 80.3% for a given year and there are 1000 randomly selected American Airlines flights.

That is, the sample proportion (p) is 0.803 and the sample size i...

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Math

Statistics

Hypothesis Testing

Related Statistics Q&A

Find answers to questions asked by student like you
Show more Q&A
add
question_answer

Q: Checking Requirements Common tests such as the SAT, ACT, Law School Admission test (LSAT), and Medic...

A: From the given information,Sample size (n) = 100Probability of success = 1/5                        ...

question_answer

Q: Sample for a Poll There are 15,524,971 adults in Florida. If The Gallup organization randomly select...

A: Given that,Sample for a Poll There are 15,524,971 adults in Florida. If The Gallup organization rand...

question_answer

Q: Independent Events Based on a Pitney Bowes survey, when 1009 consumers were asked if they are comfor...

A: Given that,Population =1009 consumersRandomly selecting 30 by without replacement.The 30 selections ...

question_answer

Q: Months If a month is randomly selected after mixing the pages from a calendar, what is the probabili...

A: Let event A denote thatgetting a month containing the letter y.The months containing letter y are ‘J...

question_answer

Q: Standard Normal Distribution. In Exercises 17–36, assume that a randomly selected subject is given a...

A: It is given that Z is the standard normal variable. The probability that the bone density test score...

question_answer

Q: If SX = 7 and SX² = 21. A new variable Y is created by multiplying each X by 3. What are SY and SY² ...

A: Here SX=7 and SX2=21. The variable Y is the obtained by multiplying each X by 3.

question_answer

Q: Suppose that A and B are mutually exclusive events such that P(A) = 0.25 and P(B) = 0.40. Determine ...

A: Special Addition Rule:

question_answer

Q: Drawing Cards. Two cards are drawn at random from an ordinary deck of 52 cards. Determine the probab...

A: a)The General Multiplication Rule:

question_answer

Q: Rain As the author is creating this exercise, a weather reporter stated that there is a 20% chance o...

A: Let event A denote the chances of rain tomorrow.The probability of chances of rain tomorrow is 20%, ...