Oppositely charged parallel plates are separated by 6.28 mm. A potential difference of 600 V exists between the plates.(a) What is the magnitude of the electric field between the plates in N/C?(b) What is the magnitude of the force on an electron between the plates in newtons?(c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.88 mm from the positive plate in Joules?

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Asked Oct 7, 2019
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Oppositely charged parallel plates are separated by 6.28 mm. A potential difference of 600 V exists between the plates.

(a) What is the magnitude of the electric field between the plates in N/C?

(b) What is the magnitude of the force on an electron between the plates in newtons?

(c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.88 mm from the positive plate in Joules? 

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Expert Answer

Step 1

Given values:

Potential difference between the plates, V = 600 V

Distance between the plates, d = 6.28 mm = 6.28 x 10-3 m

Charge on electron, q = -1.6 x 10-16 C

Step 2

(a)

The relation between the electric field and potential:

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V Ed Plugging in the given values: 600 Ex 6.28 x 10-3 E 95.54x10 9.554 x 10 N/c

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Step 3

(b)

Force on charge:

...
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F qE Plugging in the given values: F 1.6x 1019 x9.554 x 10 152.86 x 10~16 1.53x 1014 N

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