Question
Asked Sep 27, 2019
1 views

| 5x-2 | = | 2x-3 |

check_circle

Expert Answer

Step 1

Given,

help_outline

Image Transcriptionclose

15х — 21 %3D 12х — 31 Now, finding the critical point 5x 2 0 and 2x 3 0 X= 2 Now, checking the behaviour of |5x - 2|and |2x - 3 in the following intervals 2 2 3 х< 5 5 2 2 15х — 2| 12х — 3|

fullscreen
Step 2

Now,

help_outline

Image Transcriptionclose

Case 1: x < 5 15х — 2] %3D 2x — 3] 3 — (5х — 2) %3D - (2х — 3) — -5х + 2 - —2х + 3 —х- Case 2:x 3 2 15х — 2| 3 12х —3| > (5х — 2) 3 —- (2х — 3) — 5х — 2 — — 2х + 3 —х- 7

fullscreen
Step 3

Case 3:...

help_outline

Image Transcriptionclose

3 Case 3: x 2 15х — 21 %3D12x — 3| — (5х — 2) 3 (2х - 3) 5х — 2 — 2х — 3 x = Since, does not lie in the interval , co) So, it has no solution for

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in
MathAlgebra

Equations and In-equations