ormal Form grammar for this language is: S -> aB B -> bC C -> aCb | ε

Given the following DFSM M, the correct statements are: S a, b a,b T □ (aa Uab Uba U bb)* is a regular expression that generates L(M). (ab Uba)* is a regular expression that generates L(M). □S → E, S → aT, S→ bT, T→ aS, T→ bS are the regular grammar rules that generate L(M). SaT, S→ bT, TaS, TbS are the regular grammar rules that generate L(M).

Language L S->A | AX X->ABY | AB Y->ABCY | ABC BA -> AB CA -> AC CB -> BC A->a B->b C->c   Draw a state diagram for a linear-bounded automata that accepts L.

Answer the given question with a proper explanation and step-by-step solution.   Using the algorithm discussed in class, ”Big loop algorithm” show the transition diagram for a pushdown automaton (PDA) to recognize the language generated by G, which ahs the following grammer rules S →BAC A →a | b | c | ε B →bB | b C →cC | ε Fully define for the grammar G above, that is G = (....Describe in English what language the grammar G generates . Give an example showing that the grammar G above is ambiguous

1. The grammar is known as follows:P → H | PbdHH → a | (P)Asked:a. Please make a GOTO (Canonical Set) operation transition diagram

Select the Context Free Grammar below that is in the form of Chomsky Normal Form. G=( {S,a,b}, {0,1}, S, {S0b|1a, a0|OS|1aa, b➡1|1s|Obb}) ☐ G=( {S,a,b}, {0,1}, S, {Sab|1, a0|1|Sa, b→1|bs}) ☐ G=( {S,A,B}, {a,b}, S, {S AB|bA, Aa|b|SB, B→a|SB}) ☐ G=( {S,A,B}, {a,b}, S, {S-BB|b, A➡a|b|SS, B→a|SA})

1. Convert the following regular grammar into a Finite Automata S➜X XXXIXY Y➜yylyz 2-22 12 2. Convert the previous problem to a regular expression. 3. Write a grammar that generates an even number of X's.

4. Construct a Chomsky normal form grammar for L(G) for the following cfg G: G=({S,B}, {a,b,c,d}, {S→BdSaSaS|BSS|b, B->cSda|S|dcb}, S). Note: You must first remove all unit productions.

Use the bison framework to build a DFA state machine for each of the following grammars. Identify any possible conflicts causing the bottom-up parsing to fail. Make sure to complete the missing closures in each state. 1) expr expr '+' term | expr'-' term | term term – term ** primary | primary primary → ID | (' expr ')' |'-' primary 2) expr → expr '+' term | term term - term * primary | primary primary - ID | '(' expr ')' expr '+' term | expr'-' term | term term *" primary| primary primary → ID | '(' expr ')' | '' primary | ID '(' expr ')' 3) expr term

Context Free Grammar State whether it is ambiguous or unambiguous. If it is ambiguous give an equivalent unambiguous grammar. If it is unambiguous, state all the precedences and associativities enforced by the grammar. 1. <S > -> <S > - <T > | <T > - <S > | <T ><T > -> N + <T > | N | ( <S >)