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AlgebraQ&A Libraryoulary: Fill in theIs the set of all points (r, y) in a plane that are equidistant from a fixed line,and a fixed point, called theis the intersection of a plane annen a plane passes through the vertex of a double-napped47. yof points is a collection of points satisfying a given geometricof the parabola.Finding the VeParabola In E:and directrix of tgraph the parabo51. x2 +4x – 6y53. y2+x + y =Findinot on the line.49. y² + 6y +ne line that passes through the focus and the vertex of a parabola is theheof a parabola is the midpoint between the focus and the directrix.ine segment that passes through the focus of a parabola and has endpoints on the parabola is aline isto a parabola at a point on the parabola when the line intersects, but does not crossne parabola at the point.15. Focus: (0,)17. Focus: (-2, 0)16. Focus: , 0)18. Focus: (0, –1)20. Directrix: y = -4s and Applicationsching In Exercises 9-12, match the equation withraph. [The graphs are labeled (a), (b), (c), and (d).]a Paequat%3D19. Directrix: y = 222. Directrix: x = 3at the(b)21. Directrix: x = -123. Vertical axis; passes through the point (4, 6)24. Vertical axis; passes through the point (-3, –3)25. Horizontal axis; passes through the point (-2, 5)26. Horizontal axis; passes through the point (3, -2)55.x2 = 8y%3D4.-28.10 Finding the Standard Equation of aParabola In Exercises 27-36, find thestandard form of the equation of the parabola(d)-4-4with the given characteristics.++++57. x = 2y, (4,%3D21-4 -227.28.Vertex(2,6)59. y = - 2x2,8.Focusy = 4x61. Flashlight410. x = 2y•Focus(-3, 0)|3D3= -8y12. y = - 12x(2, 4)focus of the2%3DVertex8 12vertex of thaFinding the Standard Equation of aParabola In Exercises 13-26, find thestandard form of the equation of the parabolawith the given characteristic(s) and vertex atthe origin.(-4, 0)-8-1 t1 2 3 4 5 6a cross sects6.on the posia29. Vertex: (6, 3); focus: (4, 3)30. Vertex: (1, –8); focus: (3, –8)31. Vertex: (0, 2); directrix: y = 414.8-Focus(-4.5, 0)11++-8 -432. Vertex: (1, 2); directrix: y = - 133. Focus: (2, 2); directrix: x = -2Focus10,1)34. Focus: (0, 0); directrix: y = 835. Vertex: (3, -3); vertical axis; passes through the pome(0,0)4-6 -2+ 2 636. Vertex: (-1, 6); horizontal axis; passes through thepoint (-9, 2)Figure for62. Satellitedish is at thequation f4-2.++++Question

Asked Feb 19, 2020

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