Question
Asked Sep 19, 2019
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Out of an urn containing 8 green marbles and 10 blue marbles, three marbles are drawn in succession. Find the probability that all barbles are blue if

(a) replacement is allowed

(b) no replacement is allowed

 

 

 

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Step 1

Solution:

We are given that an urn contains 8 green marbles and 10 blue marbles.

(a) The probability of all three marbles are blue if replacement is allowed

 

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P(al blue marbles) P(First blue)x P(Second blue)x PCThird blue) 10 10 10 X_X 18 18 18 1000 = 5832 -0.1715

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Step 2

(b) Probability of all three marbles are blue if replacement is not allowed.

So here the marble will not be replaced back to an urn. So we will have 18 marb...

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P(al blue marbles) P(First blue)x P(Second blue)x PCThird blue) 10 9 X X 18 17 16 720 4896 =0.1471

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