OvedGiven the following hypotheses:He: 430Ht430A random sample of 9 observations is selected from a normal population. The sample mean was 437 and the sample standarddeviation was 8. Using the 0.01 significance level:a. State the decision rule. (Negative amount should be Indlcated by a mninus sign. Round your answers to 3 decmal places.)Reject Ho when the test statistic isthe interyalb. Compute the value of the test statistic. (Round your anewer to 3 declmal places.)velte of thetest statistio

Given:From the data, sample mean is = 437 and the Sample standard deviation is s = 8, and the…

Answered: Oved Given the following hypotheses:…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Given ˆpp^ = 0.2286 and N = 35 for the high income group,Test the claim that the proportion of children in the high income group that drew the nickel too large is smaller than 50%. Test at the 0.1 significance level. Give all answers correct to 3 decimal places.b) The test statistic value is: c) Using the P-value method, the P-value is:
Given ˆpp^ = 0.3714 and N = 35 for the high income group,Test the claim that the proportion of children in the high income group that drew the nickel too large is smaller than 50%. Test at the 0.1 significance level. Give all answers correct to 3 decimal places.a) The test statistic value is: ?b) Using the P-value method, the P-value is: ?
For each of the tests, what would be the conclusion if the test were carried out using the α = 0.05 level of significance? H0 : µ = 120, H1:µ ≠ 120, n = 36, S.D of population= 10.3, sample mean = 117.0 Should the null be rejected?
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of 4 days last month. Day 1234Day shift12121619Afternoon shift12101618 At the 0.10 significance level, can we conclude there are more defects produced on the day shift? Hint: For the calculations, assume the day shift as the first sample. Required: a. What is the p-value? NOTE: P-value calculators are available through online search.
In a random sample of data for the number of rooms in apartments, the summary statistics are n=197197, x =5.585.58, s=2.022.02. Use a 0.10 significance level to test the claim that the population mean of the number of rooms in apartments is less than 6.00. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
Consider the following computer output:One-sample TTest of µ = 12 vs µ 6= 12Variable N Mean StDev SE Mean t px 10 12.564 ? 0.296 ? ?a) How many degrees of freedom are there on thet-test statistic?b) Fill in the missing items.c) Calculate the p-value. What conclusions wouldyou draw?
Consider the following hypothesis test:H0 : μ ≤12Ha : μ >12 A sample of 25 provided a sample mean 14 and standard deviation 4.32. Computeand state your conclusion using α = 0.05.
The worker on examining his 20 rainfall sample points concluded that it is more than likely to rain on this May 1st. Describe two or three statistical steps he took to arrive at this conclusion.
The one-sample ?t‑statistic for a test of ?0:?=0H0:μ=0 versus ?1:?≠0H1:μ≠0 based on ?=15n=15 observations has the value ?=−1.757t=−1.757, where ?0H0 and ?1H1 are the null and alternative hypotheses, respectively. The sample size is denoted by ?n. Use this ?t‑table to determine which two ?-valuesP-values bracket the ?-valueP-value of the test. Report your answer as listed in the given ?t‑table. lower limit=lower limit= upper limit=upper limit=
The followingare the prices of a sanitizer sold at a few selected stores in a district A during the pandamic. Baesd on the sample data, at 0.05 level of signifinance, can we conclude the average price of the sanitizer in district A is RM25? Make your conclusion using p-value approach, with the aid of excel. RM20.00,RM20.50,RM29.50,RM20.70,RM20.20,RM18.70,RM23.00
In a hypothesis test with hypotheses H0 :pless than or greater than 0.58 and H1 >0.58 , a random sample of size 1,165 produced a sample proportion of 0.6160. The test is to be made at the 2.5% significance level. What is the value of the test statistic, z, rounded to three decimal places?
The one-sample ?t‑statistic for a test of ?0:?=42H0:μ=42 versus ?1:?<42H1:μ<42 based on ?=15n=15 observations has the value ?=−1.757t=−1.757, where ?0H0 and ?1H1are the null and alternative hypotheses, respectively. The sample size is denoted by ?n. Use this ?t‑table to determine which two ?-valuesP-values bracket the ?-valueP-value of the test. Report your answers in decimal form as listed in the ?t‑table. SEE PICTURE BELOW FOR FULL QUESTION AND ANSWER NEEDED. THANK YOU!

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