Over the past several months, an adult patient has been treated for tetany (severe muscle spasms). This condition is associated with an average total calcium level below 6 mg/dl. Recently, the patient's total calcium tests gave the following readings (in mg/dl). Assume that the population of x values has an approximately normal distribution.9.38.410.18.79.49.810.09.911.212.1(a) Use a calculator with mean and sample standard deviation keys to find the sample mean reading x and the sample standard deviation s. (Round your answers to two decimal places.)x = mg/dls = mg/dl(b) Find a 99.9% confidence interval for the population mean of total calcium in this patient's blood. (Round your answer to two decimal places.)lower limit     mg/dlupper limit     mg/dl(c) Based on your results in part (b), do you think this patient still has a calcium deficiency? Explain.Yes. This confidence interval suggests that the patient may still have a calcium deficiency.Yes. This confidence interval suggests that the patient no longer has a calcium deficiency.No. This confidence interval suggests that the patient may still have a calcium deficiency.No. This confidence interval suggests that the patient no longer has a calcium deficiency.

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Asked Jul 7, 2019
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Over the past several months, an adult patient has been treated for tetany (severe muscle spasms). This condition is associated with an average total calcium level below 6 mg/dl. Recently, the patient's total calcium tests gave the following readings (in mg/dl). Assume that the population of x values has an approximately normal distribution.

9.3 8.4 10.1 8.7 9.4 9.8 10.0 9.9 11.2 12.1
(a) Use a calculator with mean and sample standard deviation keys to find the sample mean reading x and the sample standard deviation s. (Round your answers to two decimal places.)
x =  mg/dl
s =  mg/dl

(b) Find a 99.9% confidence interval for the population mean of total calcium in this patient's blood. (Round your answer to two decimal places.)
lower limit      mg/dl
upper limit      mg/dl

(c) Based on your results in part (b), do you think this patient still has a calcium deficiency? Explain.
Yes. This confidence interval suggests that the patient may still have a calcium deficiency.
Yes. This confidence interval suggests that the patient no longer has a calcium deficiency.
No. This confidence interval suggests that the patient may still have a calcium deficiency.
No. This confidence interval suggests that the patient no longer has a calcium deficiency.
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Expert Answer

Step 1

In this question, we have the patients calcium reading, using that we have to find the Mean, Standard deviation, then we have to find the 99.9% confidence interval and then we have to draw the conclusion.

 

Step 2

The calculations for mean and standard deviation have shown below.

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ΣΧ Mean 9.3 86.49 n 8.4 70.56 98.9 =9.89 10 10.1 102.01 Mean 8.7 75.69 9.4 88.36 (Σ) 9.8 96.04 Σx. 10 100 Standard Deviation 98.01 9.9 n-1 11.2 125.44 98.92 989.01- 10 12.1 146.41 Sum 98.9 989.01 Standard Deviation 9 Standard Deviation =1.1

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Step 3

The calculations for the confidence inter...

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Confidence Interval = | x ±t} * {n | Confidence Interval =| 9.89 ±tro.001*10 1.1 1.1 Confidence Interval =| 9.89± 4.781x- V10 Confidence Interval =[8.227,11.553]

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