Oxygen gas can be prepared by heating potassium chlorate according to the following equation: 2KCIO3(s)2KCI(s) + 302(g) The product gas, O2, is collected over water at a temperature of 25 °C and a pressure of 754 mm Hg. If the wet O, gas formed occupies a volume of 9.42 L, the number of grams of O2 formed is g. The vapor pressure of water is 23.8 mm Hg at 25 °C.

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Chapter5: The Gaseous State
Section: Chapter Questions
Problem 5.117QP: Liquid oxygen was first prepared by heating potassium chlorate, KClO3, in a closed vessel to obtain...
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Oxygen gas can be prepared by heating potassium chlorate according to the following equation:
2KCI03(s)2KCI(s) + 302(g)
The product gas, O2, is collected over water at a temperature of 25 °C and a pressure of 754 mm Hg. If the wet O2 gas formed occupies a volume of 9.42 L, the
number of grams of O2 formed is
g. The vapor pressure of water is 23.8 mm Hg at 25 °C.
Transcribed Image Text:Oxygen gas can be prepared by heating potassium chlorate according to the following equation: 2KCI03(s)2KCI(s) + 302(g) The product gas, O2, is collected over water at a temperature of 25 °C and a pressure of 754 mm Hg. If the wet O2 gas formed occupies a volume of 9.42 L, the number of grams of O2 formed is g. The vapor pressure of water is 23.8 mm Hg at 25 °C.
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