P17A.1 The following initial-rate data were obtained on the rate of binding ofglucose with the enzyme hexokinase present at 1.34 mmol dm. What is (a)the order of reaction with respect to glucose, (b) the rate constant?C,HO/(mmoldm)1.001.543.124.02v/(mol dms)7.620.05.015.5

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Asked Nov 7, 2019
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P17A.1 The following initial-rate data were obtained on the rate of binding of
glucose with the enzyme hexokinase present at 1.34 mmol dm. What is (a)
the order of reaction with respect to glucose, (b) the rate constant?
C,HO/(mmoldm)
1.00
1.54
3.12
4.02
v/(mol dms)
7.6
20.0
5.0
15.5
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P17A.1 The following initial-rate data were obtained on the rate of binding of glucose with the enzyme hexokinase present at 1.34 mmol dm. What is (a) the order of reaction with respect to glucose, (b) the rate constant? C,HO/(mmoldm) 1.00 1.54 3.12 4.02 v/(mol dms) 7.6 20.0 5.0 15.5

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Expert Answer

Step 1

Chemical reaction is given by:

С,Н1206 + HK - C,H1206 — НК
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С,Н1206 + HK - C,H1206 — НК

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Step 2

Rate equation can be given by:

- k[CgH1206[HK]
5 k(1)m(1.34)" R
7.6 k(1.54)" (1.34)" R2
Rate
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- k[CgH1206[HK] 5 k(1)m(1.34)" R 7.6 k(1.54)" (1.34)" R2 Rate

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Step 3

Calculation for Order...

k(1 x 103)m(1.34 x 103)"
k(1.54 x 10-3)m (1.34 x 10-3)"
5
R2
7.6
(1 x 103)m
(1.54 x 10-3)m
5
7.6
5
1
In
= m x In
(1.54)
7.6
-0.4187 = m x (-0.4318)
0.4187
0.97 1
m
0.4318
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k(1 x 103)m(1.34 x 103)" k(1.54 x 10-3)m (1.34 x 10-3)" 5 R2 7.6 (1 x 103)m (1.54 x 10-3)m 5 7.6 5 1 In = m x In (1.54) 7.6 -0.4187 = m x (-0.4318) 0.4187 0.97 1 m 0.4318

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