Part 4 of 6-Analyze (b) The electric field between the capacitor plates is given by E = 0/ɛ so we have 8.85 x 10-12 c2/N m2)( 1.19 10ʻ V/m) 05315 Your response is off by a multiple of ten. × 10 8 C/m² = nC/m².

Part 4 of 6-Analyze (b) The electric field between the capacitor plates is given by E = 0/ɛ so we have 8.85 x 10-12 c2/N m2)( 1.19 10ʻ V/m) 05315 Your response is off by a multiple of ten. × 10 8 C/m² = nC/m².

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter7: Electric Potential

Section: Chapter Questions

Problem 41P: An electron is to be accelerated in a uniform electric field having a strength of 2.00106 V/m. (a)...

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I need help with the calculation please.

Part 4 of 6 -Analyze
(b) The electric field between the capacitor plates is given by E = 0/ɛ,
so we have
8.85 x 10-12 c2/N m2)( 1.19
10ʻ V/m)
05315
Your response is off by a multiple of ten. × 10-8 C/m² =
nC/m².
Submit
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