Part AConsider a long coaxial cable made of two coaxial cylindrical conductors that carry equal currents I inopposite directions (see figure). The inner cylinder is a small solid conductor of radius a. The outer cylinderis a thin walled conductor of outer radius 6, electrically insulated from the inner conductor. Calculate the selfinductance per unit length of this coaxial cable.(L is the inductance of part of the cable and l isthe length of that part.) Due to what is known asthe "skin effect", the current I flows down the(outer) surface of the inner conducting cylinderand back along the outer surface of the outerconducting cylinder. However, you may ignore thethickness of the outer cylinder.IExpress your answer in terms of some or allthe variables I, a, b, and Ho, the permeabilityof free spaceto

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Asked Nov 22, 2019
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Part A
Consider a long coaxial cable made of two coaxial cylindrical conductors that carry equal currents I in
opposite directions (see figure). The inner cylinder is a small solid conductor of radius a. The outer cylinder
is a thin walled conductor of outer radius 6, electrically insulated from the inner conductor. Calculate the self
inductance per unit length of this coaxial cable.
(L is the inductance of part of the cable and l is
the length of that part.) Due to what is known as
the "skin effect", the current I flows down the
(outer) surface of the inner conducting cylinder
and back along the outer surface of the outer
conducting cylinder. However, you may ignore the
thickness of the outer cylinder.
I
Express your answer in terms of some or all
the variables I, a, b, and Ho, the permeability
of free space
to
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Part A Consider a long coaxial cable made of two coaxial cylindrical conductors that carry equal currents I in opposite directions (see figure). The inner cylinder is a small solid conductor of radius a. The outer cylinder is a thin walled conductor of outer radius 6, electrically insulated from the inner conductor. Calculate the self inductance per unit length of this coaxial cable. (L is the inductance of part of the cable and l is the length of that part.) Due to what is known as the "skin effect", the current I flows down the (outer) surface of the inner conducting cylinder and back along the outer surface of the outer conducting cylinder. However, you may ignore the thickness of the outer cylinder. I Express your answer in terms of some or all the variables I, a, b, and Ho, the permeability of free space to

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Expert Answer

Step 1

The magnetic field through the cylinder at any distance x is,

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2ях
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В. 2ях

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Step 2

The flux through the...

B)(dA) cos
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B)(dA) cos

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Magnetic Effects of Current

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