Part A Consider a long coaxial cable made of two coaxial cylindrical conductors that carry equal currents I in opposite directions (see figure). The inner cylinder is a small solid conductor of radius a. The outer cylinder is a thin walled conductor of outer radius 6, electrically insulated from the inner conductor. Calculate the self inductance per unit length of this coaxial cable. (L is the inductance of part of the cable and l is the length of that part.) Due to what is known as the "skin effect", the current I flows down the (outer) surface of the inner conducting cylinder and back along the outer surface of the outer conducting cylinder. However, you may ignore the thickness of the outer cylinder. I Express your answer in terms of some or all the variables I, a, b, and Ho, the permeability of free space to

A 5.50 nF capacitor is charged to 12.0 V, then disconnected from the power supply and connected in series through a coil. The period of oscillation of the circuit is then measured to be 8.60 x 10-5 s. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of An oscillating circuit. Part C Calculate the total energy of the circuit. Express your answer with the appropriate units. ΜΑ 7 0 ? U = Value Units Submit Request Answer Part D Calculate the maximum current in the circuit. Express your answer with the appropriate units. D ΜΑ 7 0 ? Imax = Value Units Submit Request Answer

Part A A charged capacitor with C = 640 µF is connected in parallel to an inductor that has L = 0.450 H and negligible resistance. At an instant when the current in the inductor is i = 1.80 A , the current is increasing at a rate of di/dt = 89.0 A/s. During the current oscillations, what is the maximum voltage across the capacitor? Express your answer to three significant figures and include the appropriate units. ? HA Vmax = Value Units Submit Request Answer

Part A In an L-C circuit, C = 3.19 µF and L = 87.0 mH. During the oscillations the maximum current in the inductor is 0.855 mA You may want to review (Pages 1004 - 1008) What is the maximum charge on the capacitor? For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of An oscillating circuit. ΠΠ ΑΣφ. ? Qmaz = C Submit Request Answer Part B What is the magnitude of the charge on the capacitor at an instant when the current in the inductor has magnitude 0.491 mA ? Πνο ΑΣφ. q = Submit Request Answer

A shunt-wound DC motor with the field coils and rotor connected in parallel (Figure 1) operates from a 130 V DC power line. The resistance of the field windings, R, is 208 n. The resistance of the rotor, R. is 4.90 n. When the motor is running, the rotor develops an emf E. The motor draws a current of 4.46 A from the line. Friction losses amount to 45.0 W Part A Compute the field current Ir. Express your answer in amperes. • View Available Hint(s) Temglates Symbols undo regdo Tesel keyboard shortcuts Help A I = 0.56 Submit Prevlous Anewere X Incorrect, Try Again; 4 attempts remaining Part B Compute the rotor current I > View Available Hint(s) Figure 1 of 1 Templates Symbols undo redo Teset keyboard shortcuts Help A. I = 4,26 Submit Prevlous Answers X Incorrect; Try Again; 5 attempts remaining R ER. Part C Compute the emf E.

D Two VERY LONG wires are placed along parallel lines as shown below in the picture. The wire ON THE LEFT (at X1= 0, Z1 %3%0) has a current going in the direction shown of value, I 4.00 A The current on the RIGHT (at X2= d, Z2-0) has a current going in the direction shown of value, I2 = 6.00 A The point "P" is at the location (x36.00cm, z-10 4cm) Wire 1 Wire 2 a) The direction of current flow for wire1 and wire 2 is given by, () +1,-i (11)-7.+) 7.+1 (ii) +E,-R (iv) -K.+R

E The alternating current in an electric inductor is I = Z where E is voltage and Z= R + X₁ iis impedance. If E = 6( cos 20° + i sin 20°), R = 8, and X₁ = 2, find the current. The current is (Type your answer in the form a + bi. Round to the nearest hundredth as needed.)