PART B. Write a program MathSkills that asks the user to enter 3 numbers. Perform simple computations and output the results EXACTLY as shown below (depending on the user input). Pay attention to spaces, lines, and upper- and lower-case. The two examples below should make it clear what is expected. In the first example, the program displays the instructions and then the user types 5, 3, and 7 each separated by a space and presses enter. Then the program displays the output based on the user input. Enter THREE numbers and I will show you my math skills: 5 3 7 Check this out: 5 + 3 -7 = 1 7 = -16 5 - 3 * (5 - 3) * 7 = 14 5 squared is 25
PART B. Write a program MathSkills that asks the user to enter 3 numbers. Perform simple computations and output the results EXACTLY as shown below (depending on the user input). Pay attention to spaces, lines, and upper- and lower-case. The two examples below should make it clear what is expected. In the first example, the program displays the instructions and then the user types 5, 3, and 7 each separated by a space and presses enter. Then the program displays the output based on the user input. Enter THREE numbers and I will show you my math skills: 5 3 7 Check this out: 5 + 3 -7 = 1 7 = -16 5 - 3 * (5 - 3) * 7 = 14 5 squared is 25
C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter4: Selection Structures
Section4.3: Nested If Statements
Problem 7E
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Question
Is there a way to condense my statements? I'm also getting a "bad operand type" error. I haven't learned loops or if, else statements decisions so simple code is only accepted.
import java.util.Scanner;
public class MathSkills
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.print("Enter Three Numbers: ");
int a = in.nextInt();
int b = in.nextInt();
int c = in.nextInt();
System.out.print("a" + "b" - "c" + "=");
System.out.println(" " + (a + b - c));
System.out.print("a" - "b" * "c" + "=");
System.out.println(" " + (a - b * c));
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