Physical Properties of Selected ElementsCopperSilverPlatinumGoldPalladiumPropertyMelting point temperatureBoiling point temperature1064 °C1768 °C1085 °C962 °C1555 °C2562 °C2162 °C2856 °C2963 °C3825°C0.384 J/g.°C 0.235 J/g.°C 0.129 J/g C 0.240 J/g.°C 0.133 J/g.°CSpecific heat of solid0.490 J/g °C 0.280 J/g.°C0.150 J/g °C0.252 J/g.°C 0.140 J/g°CSpecific heat of liquid12.5 kJ/molEnthalpy of fusion (AHfus)13.1 kJ/mol11.3 kJ/mol16.7 kJ/mol20.0 kJ/molEnthalpy of vaporization (AHvap) 300. kJ/mol330. kJ/mol380. kJ/mol255 kJ/mol490. kJ/mol

Question
Asked Nov 18, 2019
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A 50.0 g sample of solid copper is heated from 25.0 o C to 2000.0 o C, melting it in the process. Using the table calculate the total heat absorbed by the metal.

answer: 53.1 kJ

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Physical Properties of Selected Elements
Copper
Silver
Platinum
Gold
Palladium
Property
Melting point temperature
Boiling point temperature
1064 °C
1768 °C
1085 °C
962 °C
1555 °C
2562 °C
2162 °C
2856 °C
2963 °C
3825°C
0.384 J/g.°C 0.235 J/g.°C 0.129 J/g C 0.240 J/g.°C 0.133 J/g.°C
Specific heat of solid
0.490 J/g °C 0.280 J/g.°C
0.150 J/g °C
0.252 J/g.°C 0.140 J/g°C
Specific heat of liquid
12.5 kJ/mol
Enthalpy of fusion (AHfus)
13.1 kJ/mol
11.3 kJ/mol
16.7 kJ/mol
20.0 kJ/mol
Enthalpy of vaporization (AHvap) 300. kJ/mol
330. kJ/mol
380. kJ/mol
255 kJ/mol
490. kJ/mol
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Physical Properties of Selected Elements Copper Silver Platinum Gold Palladium Property Melting point temperature Boiling point temperature 1064 °C 1768 °C 1085 °C 962 °C 1555 °C 2562 °C 2162 °C 2856 °C 2963 °C 3825°C 0.384 J/g.°C 0.235 J/g.°C 0.129 J/g C 0.240 J/g.°C 0.133 J/g.°C Specific heat of solid 0.490 J/g °C 0.280 J/g.°C 0.150 J/g °C 0.252 J/g.°C 0.140 J/g°C Specific heat of liquid 12.5 kJ/mol Enthalpy of fusion (AHfus) 13.1 kJ/mol 11.3 kJ/mol 16.7 kJ/mol 20.0 kJ/mol Enthalpy of vaporization (AHvap) 300. kJ/mol 330. kJ/mol 380. kJ/mol 255 kJ/mol 490. kJ/mol

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Step 1

Heat capacity is a physical property of matter, defined as the amount of heat supplied to a given mass of a material to produce a unit change in its temperature. Heat capacity is given by:

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Q=mCAT Where. Q = Heat capacity m =mass of solid C specific heat of solid AT Change in temperature(Tfnol Tmisial

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Step 2

Given data and their conversion:

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m= 50g 0.05kg C 0.0384JgC = 384J / kg.K ) ) = 2000-25=1975°C (T AT AT 1975°C+273K . AT 2248K

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Step 3

The heat capacity using specific heat...

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Q0.05kgx384 kg K 2248Kx 1000J Q43.1k

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