QUESTION 1 Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: ĐE- dA = EA = Since, its the line charge we use the area of a cylinder surrounding the line charge E*2 TT L= / E0 But all the charged get enclosed by the cylinder area, so denc = Q %3D Deriving, we get: E = (1/2 TE0 )*( /rL) QUESTION 3 Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures. The current in the light bulb is: | = milliamperes The total amount of charge passing through the filament in t= 5.00 s is: Q = coulombs Since a single electron has a charge of -1.60× 10¬19 C, the number of electrons passing through the filament in t=5.00 s is: N= x 1019 electrons

QUESTION 1 Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: ĐE- dA = EA = Since, its the line charge we use the area of a cylinder surrounding the line charge E2 TT L= / E0 But all the charged get enclosed by the cylinder area, so denc = Q %3D Deriving, we get: E = (1/2 TE0 )( /rL) QUESTION 3 Suppose 1.67 C of charge passes through the filament of a light bulb in 2.00 seconds. How many electrons pass through the filament in 5.00 s? Express all numerical values in three significant figures. The current in the light bulb is: | = milliamperes The total amount of charge passing through the filament in t= 5.00 s is: Q = coulombs Since a single electron has a charge of -1.60× 10¬19 C, the number of electrons passing through the filament in t=5.00 s is: N= x 1019 electrons

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter19: Electric Forces And Electric Fields

Section: Chapter Questions

Problem 60P: A long, straight wire is surrounded by a hollow metal cylinder whose axis coincides with that of the...

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A thin, square, conducting plate 50.0 cm on a side lies in the xy plane. A total charge of 4.00 108 C is placed on the plate. Find (a) the charge density on each face of the plate, (b) the electric field just above the plate, and (c) the electric field just below the plate. You may assume the charge density is uniform.
A long, straight wire is surrounded by a hollow metal cylinder whose axis coincides with that of the wire. The wire has a charge per unit length of , and the cylinder has a net charge per unit length of 2. From this information, use Gausss law to find (a) the charge per unit length on the inner surface of the cylinder, (b) the charge per unit length on the outer surface of the cylinder, and (c) the electric field outside the cylinder a distance r from the axis.
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Figure P15.49 shows a closed cylinder with cross-sectional area A = 2.00 m2. The constant electric field E has magnitude 3.50 103 N/C and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines paw through the curved surface. Calculate the electric flux through the cylinder's (a) lop and (b) bottom surface, (c) Determine the amount of charge inside the cylinder. Figure P15.49
Example 23.3 derives the exact expression for the electric field at a point on the axis of a uniformly charged disk. Consider a disk of radius R = 3.00 cm having a uniformly distributed charge of +5.20 C. (a) Using the result of Example 23.3, compute the electric field at a point on the axis and 3.00 mm from the center. (b) What If? Explain how the answer to part (a) compares with the field computed from the near-field approximation E = /20. (We derived this expression in Example 23.3.) (c) Using the result of Example 23.3, compute the electric field at a point on the axis and 30.0 cm from the center of the disk. (d) What If? Explain how the answer to part (c) compares with the electric field obtained by treating the disk as a +5.20-C charged particle at a distance of 30.0 cm.
Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: (contour integral E with rightwards harpoon with barb upwards on top) * (stack d A with rightwards harpoon with barb upwards on top) = ___________ /epsilon0 EA = ___________ / epsilon0 Since, its the line charge we use the area of a cylinder surrounding the line charge E*2pi ___________ L= ___________ / epsilon0 But all the charged get enclosed by the cylinder area, so qenc = Q Deriving, we get: E = (1/2(pi*epsilon0))*(___________ /rL) **see picture for the symbols used
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