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Asked Dec 19, 2019
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Given data: 5280 ft Initial speed of the ball, u = 95.0 mi/h =95.0×- 3600 s -=139.33 ft/s Horizontal distance, x = 60.5 ft Angle, e =0° Acceleration due to gravity, g = 9.8 m/s² = 32.2 ft/s²

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Projectile equation: y = x tan 0 – 2 u cos?e 32.2 |(60.5)* xcos (0) 60. = 60.5 x tan 0° (60.5) x cos (0), (-Ve indicate the drop) =-16.1 ft

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