# please help i have no ideaA 578−g piece of copper tubing is heated to 89.5°C and placed in an insulated vessel containing 159 g of water at 22.8°C. Assuming no loss of water and a heat capacity for the vessel of 10.0 J/°C, what is the final temperature of the system (c of copper = 0.387 J/g·°C)?

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A 578−g piece of copper tubing is heated to 89.5°C and placed in an insulated vessel containing 159 g of water at 22.8°C. Assuming no loss of water and a heat capacity for the vessel of 10.0 J/°C, what is the final temperature of the system (c of copper = 0.387 J/g·°C)?

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Step 1

The amount of heat lost by the metal(qm) is equal to amount of heat gained by water(qw) and vessel qv . This is shown in equation (1) in which mm is the mass of metal copper, cm is the specific heat for metal, ∆tm is the change in temperature of the metal, mw is the mass of water , cw is the specific heat for water,  ∆tis the change in temperature of the water and cv is the heat capacity for vessel.

Step 2

Substitute 578 g for mm, (89.5- Tf)○C for ∆tm, 0.387 J/g.○C 159 g for mw, 4.184 J/g○C for cw and (Tf -22.8)○C for ∆tw  and 10.0 J/○C for c...

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