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Asked Nov 10, 2019
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Please help with 1 and 2 of possible. 

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Expert Answer

Step 1

1. The given series is

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3" (n) (2n) 2"у Σ 3" (п!) Here, a (2п)!

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Step 2

Check whether the series is converges or diverges.

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3+1 (2(n+1)! 3" (n!) |(2n)! 3 (+1))(2n) |(2n+2) 3(n) (n+1 (2n)(2n +1)(2n+ 2) (п)* а1 lm lim no = lim X 3" (п!)* (2n) =lim n X 3(n+ 2 = lim -y2n 12n 2) 2 1 311 = lim 2 2+ 2 3 -<1 4 =_ By ratio test, the given series is converges

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Step 3
  1.  

The given series is

...
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(n +1) 13"(5+Inn)" (n+1) 3" (5+In n) Here

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