Problem 10:While preparing a laboratory experiment on capacitors, you connectan E-4.5 V DC power supply to fully charge an old capacitor that is marked C- 330 HFYour lab assistant hooks up the circuit as shown below. When the switch S is at point a, thecapacitor is connected to the power supply. When the switch S is at point b, the capacitor isdisconnected from the power supply and connected to a voltmeter, V. The voltmeter has aninternal resistance R-10.0 MS2alOtheexpertta.comPart (a) The capacitor is initially uncharged, when the switch is moved to positiona, hooking the capacitor C to the power supply. What will happen to the charge on thecapacitor?It will quickly (but not instantaneously) increase to a maximum valueCorrect!Part (b) Calculate the charge on the capacitor (in Coulombs) when it is fullycharged by the power supplyPart (c) After the capacitor is fully charged, you switch the switch to position b attime t-0 seconds. The voltmeter initially reads 4.5 V. After how much elapsed time (inseconds) would you expect the voltmeter to read 1/2 its initial value?Part (d) When you actually move the switch to point b, the voltmeter shows itonly takes 1000.0 s for the voltage to drop to half its initial value. Which of the following arepossible explanations of the observed behavior of this circuit? Select all that apply.OThe dielectric in the capacitor has degraded over time,decreasing the effective capacitance of the capacitor.OThe capacitor has been physically damaged, effectivelybringing the plates closer together.OThe internal resistance of the volt-meter is significantlylower than 10 ΜΩOThe internal resistance of the power supply is acting inseries with the capacitor, decreasing the overallresistance of the circuitOThe internal resistance of the power supply is acting inparallel with the capacitor, decreasing the overallresistance of the circuitSubmitHintFeedbackI give up!

Question
Asked Mar 7, 2019
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Problem 10:
While preparing a laboratory experiment on capacitors, you connect
an E-4.5 V DC power supply to fully charge an old capacitor that is marked C- 330 HF
Your lab assistant hooks up the circuit as shown below. When the switch S is at point a, the
capacitor is connected to the power supply. When the switch S is at point b, the capacitor is
disconnected from the power supply and connected to a voltmeter, V. The voltmeter has an
internal resistance R-10.0 MS2
al
Otheexpertta.com
Part (a) The capacitor is initially uncharged, when the switch is moved to position
a, hooking the capacitor C to the power supply. What will happen to the charge on the
capacitor?
It will quickly (but not instantaneously) increase to a maximum value
Correct!
Part (b) Calculate the charge on the capacitor (in Coulombs) when it is fully
charged by the power supply
Part (c) After the capacitor is fully charged, you switch the switch to position b at
time t-0 seconds. The voltmeter initially reads 4.5 V. After how much elapsed time (in
seconds) would you expect the voltmeter to read 1/2 its initial value?
Part (d) When you actually move the switch to point b, the voltmeter shows it
only takes 1000.0 s for the voltage to drop to half its initial value. Which of the following are
possible explanations of the observed behavior of this circuit? Select all that apply.
OThe dielectric in the capacitor has degraded over time,
decreasing the effective capacitance of the capacitor.
OThe capacitor has been physically damaged, effectively
bringing the plates closer together.
OThe internal resistance of the volt-meter is significantly
lower than 10 ΜΩ
OThe internal resistance of the power supply is acting in
series with the capacitor, decreasing the overall
resistance of the circuit
OThe internal resistance of the power supply is acting in
parallel with the capacitor, decreasing the overall
resistance of the circuit
Submit
Hint
Feedback
I give up!
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Problem 10: While preparing a laboratory experiment on capacitors, you connect an E-4.5 V DC power supply to fully charge an old capacitor that is marked C- 330 HF Your lab assistant hooks up the circuit as shown below. When the switch S is at point a, the capacitor is connected to the power supply. When the switch S is at point b, the capacitor is disconnected from the power supply and connected to a voltmeter, V. The voltmeter has an internal resistance R-10.0 MS2 al Otheexpertta.com Part (a) The capacitor is initially uncharged, when the switch is moved to position a, hooking the capacitor C to the power supply. What will happen to the charge on the capacitor? It will quickly (but not instantaneously) increase to a maximum value Correct! Part (b) Calculate the charge on the capacitor (in Coulombs) when it is fully charged by the power supply Part (c) After the capacitor is fully charged, you switch the switch to position b at time t-0 seconds. The voltmeter initially reads 4.5 V. After how much elapsed time (in seconds) would you expect the voltmeter to read 1/2 its initial value? Part (d) When you actually move the switch to point b, the voltmeter shows it only takes 1000.0 s for the voltage to drop to half its initial value. Which of the following are possible explanations of the observed behavior of this circuit? Select all that apply. OThe dielectric in the capacitor has degraded over time, decreasing the effective capacitance of the capacitor. OThe capacitor has been physically damaged, effectively bringing the plates closer together. OThe internal resistance of the volt-meter is significantly lower than 10 ΜΩ OThe internal resistance of the power supply is acting in series with the capacitor, decreasing the overall resistance of the circuit OThe internal resistance of the power supply is acting in parallel with the capacitor, decreasing the overall resistance of the circuit Submit Hint Feedback I give up!

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Expert Answer

Step 1

a) If the capacitor is initially uncharged, when the switch is moved to a, hooking the capacitor C to the power supply, the capacitor will quickly get the maximum value of charge.

The charge is,

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Step 2

Answer Qmax

Step 3

b)

The expression for the charge when th...

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