Problem 15.74Two smooth disks A and B each have a mass of 0.5 kg. Both disks are moving with thevelocities shown when they collide. Suppose that (vA) = 6 m/s, (vB) =5 m/s(Figure 1)Part ADetermine the coefficient of restitution between the disks if after collision B travels along a line, 30° counterclockwise from the y axisExpress your answer using three significant figures.nν ΑΣφ?vece =SubmitRequest AnswerProvide FeedbackFigure1 of 1(VA)1XABMail

Mass of disk A and B =0.5 kgThe velocity of A = 6 m/sThe velocity of B = 5 m/sAfter collision B…

Answered: Problem 15.74 Two smooth disks A and B…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The two spheres shown collide. the weight of the first sphere (W1) is 40 N while that of the second is (W2) is 30N. assuming that the second sphere's velocity (v2) is 14 m/s and the first sphere's velocity (v1) is 16 m/s along the their respective angles. theta 1(θ1)=30 degrees and theta 2(θ2)=60 degrees. Assume velocities along y will be equal before and after impact. The coefficient of restitution is 0.57. A.) Determine the velocity of the 30N sphere after impact (m/s) B.) Determine the Velocity of the 40N sphere after impact (m/s) C.) Determine the angle of the velocity after impact of the 40N sphere with the horizontal (degrees) D.) Determine the angle of the velocity after impact for the 30N sphere with the vertical (degrees)
For a perfectly elastic collision, u1+v1=u2+v2, or alternatively, u2−u1=v1−v2. If object 2 is initially at rest, then u2=0. Then v1−v2=−u1. However, for a partially elastic collision the relative velocity after the collision will have a smaller magnitude than the relative velocity before the collision. We can express this mathematically as v1−v2=−ru1, where r (a number less than one) is called the coefficient of restitution. For some kinds of bodies, the coefficient r is a constant, independent of v1 and v2. Show that in this case the final kinetic energy of the motion relative to the center of mass is less than the initial kinetic energy of this motion by a factor of r2. Furthermore, derive expressions for v1 and v2 in terms of u1 and r.
- The steel ball strikes the heavy steel plate with a velocityv0 = 24 m/s at an angle of 60º with the horizontal. If thecoefficient of restitution is e = 0.8, compute the velocity v andits direction θ with which the ball rebounds from the plate.{20.5m/s, 54.18º}
Scientists observe an approaching asteroid that is on a collision course with Earth. They devise a plan to launch a rocket that will collide with the asteroid inelastically and stop it. The mass of the asteroid is 7500 kg, and it is approaching Earth at 85 m/s. If the rocket has a mass of 900 kg, approximately what velocity must it have to completely stop the asteroid after collision?
Situation 01. A 4kg ball and 3kg ball move on a smooth plane along a straight path with speeds equivalent to 6m/s going to the right and 8 m/s going to the left, respectively a. Determine the speed of the 3kg ball after impact if the impact is elastic. b. Determine the speed of the 3kg ball after impact if the coefficient of restitution is 0.50. complete solution of impulse and momentum
A 70-g ball B dropped from a height h0 = 1.5 m reaches a height h2 = 0.25 m after bouncing twice from identical 210-g plates. Plate A rests directly on hard ground, while plate C rests on a foam-rubber mat. Determine (a) the coefficient of restitution between the ball and the plates, (b) the height h1 of the ball’s first bounce.
Determine the coefficient of restitution e for a steel ball dropped from rest at a height h above a heavy horizontal steel plate if the height of the second rebound is h2. Can someone please explain to me how the book is getting that equation?
Two spheres of different masses and initial velocities collide with each other on frictionless surface, as shown in Figure 5. Assume the collision is direct central and the coefficient of restitution e = 0.8, determine their velocities after the collision.
(a) Explain briefly the principle of the conservation of Linear Momentum(b) A pile driver, mass 1 tonne, falls freely through a distance of 5m before striking the pile, mass 0.5 tonnes. When the pile is nearly fally driven, the average resistance is 700kN. Determine the penetration per blow at that stage and evaluate the kinetic energy lost at impact
A sphered, of mass 2m, moving speed 2u on a smooth horizontal plane, collides directly with another sphere B of radius and of mass m which is moving with speed u in the opposite direction. Given that the coefficient of restitution between the spheres is ½ , findTheir speeds after the collision,The magnitude of the instantaneous impulse,The loss in kinetic energy caused by the collision,After a short interval, the sphere A is given a horizontal impulse of magnitude 7mu so that it collides again directly with sphere B. Find the speed of A and the speed of B after second impact.
Compare the total momentum before and total momentum after of elastic and perfectly inelastic collision. Compare the total KE before and total KE after of elastic and perfectly inelastic collision.
A ball is thrown with a 30 m/s horizontal velocity towards a vertical rod. The 2m rod is pinned at the top of the rod (point A) and it is free to rotate around this point. The ball contacts the rod 1.2m below A with a coefficient of restitution of .75. Assuming the rod has a mass of 10kg and the ball has a mass of .1kg, determine the velocity of the ball after impact.

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