Problem 2: An ice cube (mass 30g) at 0°C is left sitting on the kitchen table, where it gradually melts. The temperature in the kitchen is 25°C. a) Calculate the change in the entropy of the ice cube as it melts into water at 0°C. (Don’t worry about the fact that the volume changes somewhat.) b) Calculate the change in the entropy of the water (from melted ice) as its temperature rises from 0°C to 25°C. c) Calculate the change in the entropy of the kitchen as it gives up heat to the melting ice/water. d) Calculate the net change in the entropy of the universe during this process. Is the net change positive, negative or zero? Is this what you would expect? Note that the latent heat L for melting ice is L, = 3.33 × 105J/kg and the specific heat from freezing to boiling is about Cy = 4.18 × 10³J/kg K. Answers to one digit (but you need to provide two digits): (a) AS = 40 J/K; (b) AS = 10 J/K; (c) AS =-40 J/K; (d) AStotal = 4 J/K.

Problem 2: An ice cube (mass 30g) at 0°C is left sitting on the kitchen table, where it gradually melts. The temperature in the kitchen is 25°C. a) Calculate the change in the entropy of the ice cube as it melts into water at 0°C. (Don’t worry about the fact that the volume changes somewhat.) b) Calculate the change in the entropy of the water (from melted ice) as its temperature rises from 0°C to 25°C. c) Calculate the change in the entropy of the kitchen as it gives up heat to the melting ice/water. d) Calculate the net change in the entropy of the universe during this process. Is the net change positive, negative or zero? Is this what you would expect? Note that the latent heat L for melting ice is L, = 3.33 × 105J/kg and the specific heat from freezing to boiling is about Cy = 4.18 × 10³J/kg K. Answers to one digit (but you need to provide two digits): (a) AS = 40 J/K; (b) AS = 10 J/K; (c) AS =-40 J/K; (d) AStotal = 4 J/K.